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2025-02-18 15:33:50
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2025-02-18 15:32:29
-82,15 kJ.
2025-02-18 15:29:45
A.Fe0 + HN+5O3 → Fe+3(NO3)3+ N+2O + H2O
-Vậy ta có phương trình: Fe + 4HNO3 → Fe(NO3)3 + NO↑ + 2H2O
B.FeSO4 + KMnO4 + H2SO4 → Fe2(SO4)3 + K2SO4 + MnSO4 + H2O
5
×
2
×
∣
∣
∣
2
+
2
F
e
→
2
+
3
F
e
+
2
e
+
7
M
n
+
5
e
→
+
2
M
n
10FeSO4 + 2KMnO4 + 8H2SO4 → 5Fe2(SO4)3 + K2SO4 + 2MnSO4 + 8H2O
2025-02-18 15:29:45
A.Fe0 + HN+5O3 → Fe+3(NO3)3+ N+2O + H2O
-Vậy ta có phương trình: Fe + 4HNO3 → Fe(NO3)3 + NO↑ + 2H2O
B.FeSO4 + KMnO4 + H2SO4 → Fe2(SO4)3 + K2SO4 + MnSO4 + H2O
5
×
2
×
∣
∣
∣
2
+
2
F
e
→
2
+
3
F
e
+
2
e
+
7
M
n
+
5
e
→
+
2
M
n
10FeSO4 + 2KMnO4 + 8H2SO4 → 5Fe2(SO4)3 + K2SO4 + 2MnSO4 + 8H2O