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bạn nên đăng câu hỏi 1 lần, tránh trùng lặp nha bạn
76 + 6 = 82
homeworks bỏ s nha bạn, vì đó là danh từ không đếm được
⇒ homework
bài 20:
\(a.4^{n}=256\)
\(4^{n}=4^4\)
⇒ n = 4
b . \(9^{5n-8}=81\)
\(9^{5n-8}=9^2\)
⇒ 5n - 8 = 2
5n = 2 + 8
5n = 10
n = 10 : 5 = 2
c. \(3^{n+2}:27=3\)
\(3^{n+2}=3\cdot27\)
\(3^{n+2}=81\)
\(3^{n+2}=3^4\)
⇒ n + 2 = 4
⇒ n = 4 - 2 = 2
d. \(8^{n+2}\cdot2^3=8^5\)
\(8^{n+2}=8^5:2^3\)
\(8^{n+2}=8^4\)
⇒ n + 2 = 4
⇒ n = 4 - 2 = 2
bài 21 :
\(a.30-2x^2=12\)
\(2x^2=30-12\)
\(2x^2=18\)
\(x^2=18:2\)
\(x^2=9\)
⇒ x = 3 hoặc x = -3
b. \(\left(9-2x\right)^3=125\)
\(\left(9-2x\right)^3=5^3\)
⇒ 9 - 2x = 5
2x = 9 - 5
2x = 4
x = 4 : 2 = 2
c. \(\left(2x-2\right)^4=0\)
⇒ 2x - 2 = 0
2x = 2
x = 2 : 2 = 1
d. \(\left(x+5\right)^3=\left(2x\right)^3\)
⇒ x + 5 = 2x
⇒ 2x - x = 5
x = 5
\(a.16=\left(x-5\right)^2\)
\(\Rightarrow\left[\begin{array}{l}x-5=4\Rightarrow x=9\\ x-5=-4\Rightarrow x=1\end{array}\right.\)
vậy x thuộc {9; 1}
b. \(\left(x-1\right)^3-27=0\)
\(\Rightarrow\left(x-1\right)^3=27\)
\(\left(x-1\right)^3=3^3\)
⇒ x - 1 = 3
⇒ x = 3 + 1 = 4
c. \(\left(7x-11\right)^3-2^5\cdot5^2=200\)
\(\left(7x-11\right)^3-800=200\)
\(\left(7x-11\right)^3=200+800\)
\(\left(7x-11\right)^3=1000\)
\(\left(7x-11\right)^3=10^3\)
⇒ 7x - 11 = 10
7x = 10 + 11
7x = 21
x = 21 : 7 = 3
d. \(x^2=x^5\)
\(\Rightarrow x^5-x^2=0\)
\(x^2\cdot\left(x^3-1\right)=0\)
\(x^2\cdot\left(x-1\right)\cdot\left(x^2+x+1\right)=0\)
\(\left[\begin{array}{l}x^2=0\Rightarrow x=0\\ x-1=0\Rightarrow x=1\\ x^2+x+1>0\forall x\end{array}\right.\)
vậy x thuộc {0; 1}
e. \(\left(3x-1\right)^{10}=\left(3x-1\right)^{20}\)
\(\Rightarrow\left(3x-1\right)^{10}\cdot\left\lbrack1-\left(3x-1\right)^{10}\right\rbrack=0\)
\(\Rightarrow\left[\begin{array}{l}\left(3x-1\right)^{10}=0\Rightarrow x=\frac13\\ \left(3x-1\right)^{10}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac13\\ \left[\begin{array}{l}3x-1=1\Rightarrow x=\frac23\\ 3x-1=-1\Rightarrow x=0\end{array}\right.\end{array}\right.\)
vậy \(x\in\left\lbrace\frac13;\frac23;0\right\rbrace\)
không được nha bạn
\(\frac{9,6\times2,5+4,8\times3,5\times2+19,2\times2}{5,6\times14,5-6,5\times0,8-4,5\times5,6-3,5\times0,8}\)
\(=\frac{9,6\times2,5+9,6\times3,5+19,2\times2}{5,6\times\left(14,5-4,5\right)-0,8\times\left(6,5+3,5\right)}\)
\(=\frac{9,6\times\left(2,5+3,5\right)+9,6\times2\times2}{5,6\times10-0,8\times10}\)
\(=\frac{9,6\times6+9,6\times4}{10\times\left(5,6-0,8\right)}\)
\(=\frac{9,6\times\left(6+4\right)}{10\times4,8}\)
\(=\frac{9,6\times10}{10\times4,8}\)
\(=\frac{9,6}{4,8}=\frac{96}{48}=2\)