rank j solo oneshot k

Ta có : \(y = 5 x - 1\)

\(\Rightarrow y = 5. \left(\right. - 5 \left.\right) - 1 = - 26\)

\(y = 5. \left(\right. - 4 \left.\right) - 1 = - 21\)

\(y = 5. \left(\right. - 3 \left.\right) - 1 = - 16\)

\(y = 5. \left(\right. - 2 \left.\right) - 1 = - 11\)

\(y = 5. \left(\right. 0 \left.\right) - 1 = - 1\)

\(y = 5. \left(\right. 15 \left.\right) - 1 = 74\)

a) \(- 3 + \left(\right. - 4 \left.\right) - \left(\right. - 3 \left.\right) + \left(\right. 2 + 7 - 10 \left.\right) = - 3 - 4 + 3 + 2 + 7 - 10 = - 5\)

b) \(3 - \left(\right. - 3 + 2 - 7 \left.\right) + \left(\right. - 4 \left.\right) = 3 + 3 - 2 + 7 - 4 = 7\)

c) \(7 + \left(\right. - 2 - 3 + 7 \left.\right) - \left(\right. - 2 \left.\right) = 7 - 2 - 3 + 7 + 2 = 17\)

d) \(- \left(\right. - 3 \left.\right) - \left(\right. - 2 + 3 - 8 \left.\right) + \left(\right. - 6 \left.\right) = 3 + 2 - 3 + 8 - 6 = 4\)

Bài 2 :

a) \(x^{2} - 2 x - \left(\right. 3 x - 2 x \left.\right) = x^{2} - 2 x - 3 x + 2 x = x^{2} - 3 x\)

b) \(- \left(\right. x^{2} + 3 x^{2} \left.\right) - \left(\right. - 5 x^{2} + 3 x \left.\right) = - x^{2} - 3 x^{2} + 5 x^{2} - 3 x = x^{2} - 3 x\)

c) \(\left(\right. x - y \left.\right) - \left(\right. x + 3 y + 1 \left.\right) = x - y - x - 3 y - 1 = - 4 y - 1\)

(0,125)5.(2,4)5=(0,125.2,4)5=(0,3)5=0,00243

\(\left(\left(\right. - 0 , 3 \left.\right)\right)^{5} . \left(\left(\right. 0 , 01 \left.\right)\right)^{3} = - 0 , 00243.0 , 000001 = - 0 , 00000000243\)

Chúc bn học tốt!

Ta có:    AB = DE

              BC = EF

vậy cần: AC = DF

a: Xét ΔMHE vuông tại H và ΔMHF vuông tại H có

ME=MF

MH chung

Do đó: ΔMHE=ΔMHF

=>HE=HF

b: ΔMHE=ΔMHF

=>\(\hat{E M H} = \hat{F M H}\)

Xét ΔMAH vuông tại A và ΔMBH vuông tại B có

MH chung

\(\hat{A M H} = \hat{B M H}\)

Do đó: ΔMAH=ΔMBH

=>MA=MB

F(x)=(a+b+c)2

\(= \left(\left(\right. a + b \left.\right)\right)^{2} + 2 \cdot c \cdot \left(\right. a + b \left.\right) + c^{2}\)

\(= a^{2} + b^{2} + 2 a b + 2 a c + 2 b c + c^{2}\)

=G(y)

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