Trần Gia Minh
Giới thiệu về bản thân
abc4−abc−1111abc⋅10+4−abc=1111abc⋅(10−1)=1111−4abc⋅9=1107abc=1107:9abc=123
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\(\overset{\overline}{a b 5} = \overset{\overline}{a b} + 230 \overset{\overline}{a b} \cdot 10 + 5 = \overset{\overline}{a b} + 230 \overset{\overline}{a b} \cdot 10 - \overset{\overline}{a b} = 230 - 5 = > \overset{\overline}{a b} \cdot \left(\right. 10 - 1 \left.\right) = 225 = > \overset{\overline}{a b} \cdot 9 = 225 = > \overset{\overline}{a b} = 225 : 9 = > \overset{\overline}{a b} = 25\)
abc4−abc−1111abc⋅10+4−abc=1111abc⋅(10−1)=1111−4abc⋅9=1107abc=1107:9abc=123
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\(\overset{\overline}{a b 5} = \overset{\overline}{a b} + 230 \overset{\overline}{a b} \cdot 10 + 5 = \overset{\overline}{a b} + 230 \overset{\overline}{a b} \cdot 10 - \overset{\overline}{a b} = 230 - 5 = > \overset{\overline}{a b} \cdot \left(\right. 10 - 1 \left.\right) = 225 = > \overset{\overline}{a b} \cdot 9 = 225 = > \overset{\overline}{a b} = 225 : 9 = > \overset{\overline}{a b} = 25\)