

Trần Khánh Linh
Giới thiệu về bản thân



































Chiều dài đám đất hình chữ nhật là:
\(60\) \(\times\) \(\dfrac{4}{3}\) = \(80\) \(\left(m\right)\)
Diện tích đám đát hình chữ nhật là:
\(60\) \(\times\) \(80\) = \(4800\) \((\)\(^{m^2}\)\()\)
Diện tích trồng cây là:
\(4800\)\(\times\) \(\dfrac{7}{12}\) = \(2800\)\((\) \(^{m^2}\)\()\)
Diện tích phần đất còn lại là:
\(4800\) \(-\) \(2800\) = \(2000\) \((\)\(^{m^2}\)\()\)
Diện tích ao thả cá là:
\(2000\) \(\times\) \(30\%\) = \(600\)\((\)\(^{m^2}\)\()\)
Đáp số: \(600\) \(^{m^2}\).
a)
\(\dfrac{-5}{9}\) \(+\) \(\dfrac{8}{15}\)\(+\) \(\dfrac{-2}{11}\)\(+\) \(\dfrac{4}{-9}\)\(+\) \(\dfrac{7}{15}\)
= \(\dfrac{-5}{9}\)\(+\) \(\dfrac{8}{15}\)\(+\) \(\dfrac{-2}{11}\)\(+\)\(\dfrac{-4}{9}\)\(+\)\(\dfrac{7}{15}\)
= (\(\dfrac{-5}{9}\)\(+\) \(\dfrac{-4}{9}\)) \(+\) ( \(\dfrac{8}{15}\)\(+\) \(\dfrac{7}{15}\))\(+\) \(\dfrac{-2}{11}\)
=\(\left(-1\right)\) \(+1\) \(+\) \(\dfrac{-2}{11}\)
= \(0+\) \(\dfrac{-2}{11}\)
= \(\dfrac{-2}{11}\)
b) (\(\dfrac{7}{2}\) \(\times\) \(\dfrac{5}{6}\)) \(+\) (\(\dfrac{7}{6}\) \(\div\) \(\dfrac{2}{7}\))
= \(\dfrac{35}{12}\) \(+\)( \(\dfrac{7}{6}\) \(\times\) \(\dfrac{7}{2}\) )
= \(\dfrac{35}{12}\) \(+\) \(\dfrac{49}{12}\)
= \(\dfrac{84}{12}\)
= \(7\)
a)
\(\dfrac{-3}{8}\)= \(\dfrac{-3.3}{8.3}\) =\(\dfrac{-9}{24}\)
\(\dfrac{5}{-12}\) = \(\dfrac{-5}{12}\) = \(\dfrac{-5.2}{12.2}\) = \(\dfrac{-10}{24}\)
Vì \(\dfrac{-9}{24}\) > \(\dfrac{-10}{24}\) nên \(\dfrac{-3}{8}\) > \(\dfrac{5}{-12}\)
Vậy \(\dfrac{-3}{8}\) > \(\dfrac{5}{-12}\).
b)
\(\dfrac{3131}{5252}\)=\(\dfrac{3131:101}{5252:101}\) = \(\dfrac{31}{52}\)
\(\dfrac{31}{52}\) = \(\dfrac{31}{52}\)
Vì \(\dfrac{3131}{5252}\) = \(\dfrac{31}{52}\)và \(\dfrac{31}{52}\)= \(\dfrac{31}{52}\) \(\Rightarrow\) \(\dfrac{3131}{5252}\)= \(\dfrac{31}{52}\)
Vậy \(\dfrac{3131}{5252}\) = \(\dfrac{31}{52}\).