HÀ GIA BẢO
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2024-11-07 18:35:30
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2024-11-05 22:29:30
a) \(\dfrac{5}{9}\)-\(\left(\dfrac{1}{3}\right)^2\)= \(\dfrac{5}{9}\)-\(\dfrac{1}{9}\)=\(\dfrac{4}{9}\)
b) \(\dfrac{1}{5}\).\(\dfrac{-3}{2}\)+\(\dfrac{-17}{2}\).\(\dfrac{1}{5}\)
= \(\dfrac{1}{5}\) . \(\left(\dfrac{-3}{2}+\dfrac{-17}{2}\right)\)
= \(\dfrac{1}{5}\). (-10)
= -2
c) 1+\(\left(\dfrac{-2}{5}+\dfrac{11}{13}\right)\)-\(\left(\dfrac{3}{5}-\dfrac{2}{13}\right)\)
= 1+\(\dfrac{-2}{5}\)+\(\dfrac{11}{13}\)- \(\dfrac{3}{5}+\dfrac{2}{13}\)
= 1+\(\left(\dfrac{-2}{5}+\dfrac{3}{5}\right)+\left(\dfrac{11}{13}+\dfrac{2}{13}\right)\)
= 1+(-1)+1
= 1