a, x+\(\dfrac{5}{6}\)=\(\dfrac{4}{3}\)

         x=\(\dfrac{4}{3}\)-\(\dfrac{5}{6}\)

         x=\(\dfrac{8}{6}\)-\(\dfrac{5}{6}\)

         x=\(\dfrac{1}{2}\)

b, x : \(2^4\)= \(8^3\)

    x : \(2^4\)= \(\left(2^3\right)^3\)

    x : \(2^4\)= \(2^9\)

         x =\(2^4\).\(2^9\)

         x =\(2^{4+9}\)

         x=\(2^{13}\)

c,\(\dfrac{13}{4}\). ( \(\dfrac{5}{52}\)- x)= \(\dfrac{1}{4}\)

          \(\dfrac{5}{52}\)-x= \(\dfrac{1}{4}\):\(\dfrac{13}{4}\)

          \(\dfrac{5}{52}\)-x=\(\dfrac{1}{4}\).\(\dfrac{4}{13}\)

           \(\dfrac{5}{52}\)-x=\(\dfrac{1}{13}\)

                 x= \(\dfrac{5}{52}\)-\(\dfrac{1}{13}\)

                 x= \(\dfrac{5}{52}\)-\(\dfrac{4}{52}\)

                 x=\(\dfrac{1}{52}\)

a,\(\dfrac{5}{9}\)-\(\left(\dfrac{1}{3}\right)^2\)=\(\dfrac{5}{9}\)-\(\dfrac{1}{9}\)=\(\dfrac{5-1}{9}\)=\(\dfrac{4}{9}\)

b,\(\dfrac{1}{5}\).\(\dfrac{-3}{2}\)+\(\dfrac{-17}{2}\).\(\dfrac{1}{5}\)=\(\dfrac{1}{5}\).(\(\dfrac{-3}{2}\)+\(\dfrac{-17}{2}\))=\(\dfrac{1}{5}\).(-10)= -2

c, 1+(\(\dfrac{-2}{5}\)+\(\dfrac{11}{13}\))-(\(\dfrac{3}{5}\)-\(\dfrac{2}{13}\))= 1+\(\dfrac{-2}{5}\)+\(\dfrac{11}{13}\)-\(\dfrac{3}{5}\)+\(\dfrac{2}{13}\)=1+(\(\dfrac{-2}{5}\)-\(\dfrac{3}{5}\))+(\(\dfrac{11}{13}\)+\(\dfrac{2}{13}\))=1+(-1)+1=1