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a,5CaC₂O₄ + 2KMnO₄ + 8H₂SO₄ → 5CaSO₄ + K₂SO₄ + 2MnSO₄ + 10CO₂↑ + 8H₂O

b,

Trong 1 ml máu:

nKMnO4 = 0,00205.4,88.10-4 = 1.10-6

→ nCa2+ = nCaC2O4 = 2,5.10-6

Trong 100 ml máu: nCa2+ = 2,5.10-4

→ mCa2+ = 2,5.10-4.40 = 0,01 gam = 10 mg

∆rH⁰298= ∆fH⁰298(Ca²+) + ∆fH⁰298(2Cl-) — ∆fH⁰298(CaCl2)

= -542,83 - 2×167,16 +795

= -82,15

a,

Chất oxi hóa : HNO3 

Chất khử : Fe
Quá trình oxi hóa : Fe ---> Fe+3 + 3e   x 1

Quá trình khử        N+5 + 3e ---> N+2   x 1 

Fe + 4HNO3 ----> Fe(NO3)3 + NO + 2H2O

b,

Chất oxi hóa : KMnO4

Chất khử : FeSO4

Quá trình oxi hóa : 2.Fe+2 ---> 2.Fe+3 + 2e  x 5

Quá trình khử : Mn+7 + 5e --> Mn+2       x 2

 2KMnO4 + 10FeSO4 + 8H2SO4 $\to$ 5Fe2(SO4)3 + 2MnSO4 + K2SO4 + 8H2O.