

Nguyễn Hoàng Thảo Hân
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Chiều dài hình chữ nhật trồng được là:
5,5:\(\dfrac{1}{4}\)=22(khóm hoa)
Chiều rộng hình chữ nhật trồng được là:
3,75:\(\dfrac{1}{4}\)=15(khóm hoa)
Số khóm hoa trồng được là:
[(22+15).2]-4=70(khóm hoa)
Vậy trồng được 70 khóm hoa.
a) \(\dfrac{1}{5}\)+\(\dfrac{4}{5}\):x=0,75
\(\dfrac{1}{5}\)+\(\dfrac{4}{5}\):x=\(\dfrac{3}{4}\)
\(\dfrac{4}{5}\):x=\(\dfrac{3}{4}\)-\(\dfrac{1}{5}\)
\(\dfrac{4}{5}\):x=\(\dfrac{11}{20}\)
x=\(\dfrac{16}{11}\)
Vậy x=\(\dfrac{16}{11}\)
b)x+\(\dfrac{1}{2}\)=1-x
2x=-\(\dfrac{1}{2}\)
2x=\(\dfrac{1}{2}\)
x=\(\dfrac{1}{4}\)
Vậy x=\(\dfrac{1}{4}\)
a)\(\dfrac{2}{3}\).\(\dfrac{5}{4}\)-\(\dfrac{3}{4}\).\(\dfrac{2}{3}\)=\(\dfrac{2}{3}\).(\(\dfrac{5}{4}\)-\(\dfrac{3}{4}\))=\(\dfrac{2}{3}\).\(\dfrac{1}{2}\)=\(\dfrac{1}{3}\)
b)2.\(\left(\dfrac{-3}{2}\right)^2\)-\(\dfrac{7}{2}\)=2.\(\dfrac{9}{4}\)-\(\dfrac{7}{2}\)=\(\dfrac{9}{2}\)-\(\dfrac{7}{2}\)=1
c) \(\dfrac{-3}{4}\).5\(\dfrac{3}{13}\)-0,75.\(\dfrac{36}{13}\)=\(\dfrac{3}{4}\).5\(\dfrac{3}{13}\)-\(\dfrac{3}{4}\).\(\dfrac{36}{13}\)
=\(\dfrac{-3}{4}\)(5\(\dfrac{3}{13}\)+\(\dfrac{36}{13}\))
=\(\dfrac{-3}{4}\).8
=-6
a)\(\dfrac{2}{3}\).\(\dfrac{5}{4}\)-\(\dfrac{3}{4}\).\(\dfrac{2}{3}\)=\(\dfrac{2}{3}\).(\(\dfrac{5}{4}\)-\(\dfrac{3}{4}\))=\(\dfrac{2}{3}\).\(\dfrac{1}{2}\)=\(\dfrac{1}{3}\)