a,(\(\dfrac{1}{2}\)+1,5).x=\(\dfrac{1}{5}\)

2.x=\(\dfrac{1}{5}\)

x=\(\dfrac{1}{5}\):2

x=\(\dfrac{1}{10}\)

b,(-1\(\dfrac{3}{5}\)+x):\(\dfrac{12}{13}\)=\(\dfrac{21}{6}\)

-1\(\dfrac{3}{5}\)+x=\(\dfrac{13}{6}\).\(\dfrac{12}{13}\)

x=2+1\(\dfrac{3}{5}\)

x=3\(\dfrac{3}{5}\)

c,(x:2\(\dfrac{1}{3}\)).\(\dfrac{1}{7}\)=\(\dfrac{-3}{8}\)

x.\(\dfrac{3}{7}\).\(\dfrac{1}{7}\)=\(\dfrac{-3}{8}\)

x=\(\dfrac{-3}{8}\):\(\dfrac{3}{49}\)

x=\(\dfrac{-49}{8}\)=6\(\dfrac{1}{8}\)

d,\(\dfrac{-4}{7}\).x+\(\dfrac{7}{5}\)=\(\dfrac{1}{8}\).\(\dfrac{-3}{5}\)

\(\dfrac{-4}{7}\)x=\(\dfrac{-3}{40}\)-\(\dfrac{7}{5}\)

x=\(\dfrac{-59}{40}\).\(\dfrac{-4}{7}\)=2\(\dfrac{93}{160}\)

a,x+\(\dfrac{1}{3}\)=\(\dfrac{1}{2}\)-\(\dfrac{5}{6}\)

x=\(-\dfrac{1}{3}\)-\(\dfrac{1}{3}\)

x=\(-\dfrac{2}{3}\)

b,\(\dfrac{3}{8}\)+\(\dfrac{5}{8}\)-\(\dfrac{1}{5}\)-x=\(\dfrac{1}{5}\)

x=1-\(\dfrac{1}{5}\)-\(\dfrac{1}{5}\)

x=\(\dfrac{3}{5}\)

a,x=7-\(\dfrac{2}{5}\)+1,62=8,22

b,x=4\(\dfrac{3}{5}\)+\(\dfrac{1}{5}\)-\(\dfrac{1}{2}\)=4\(\dfrac{3}{10}\)

c,2x-x=\(\dfrac{3}{5}\)+\(\dfrac{4}{7}\)

x=\(\dfrac{41}{35}\)

d,x=3\(\dfrac{1}{2}\)-\(\dfrac{5}{7}\)+\(\dfrac{1}{13}\)-0,25=2\(\dfrac{223}{364}\)