Nguyễn Lam Giang
Giới thiệu về bản thân
Tên: Nguyễn Lam Giang
Lớp: 6A3
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2025-01-18 21:35:21
a) 53.25−25.12+75.5353.25−25.12+75.53
=(53.25+75.53)−25.12=(53.25+75.53)−25.12
=53.(25+75)−25.12=53.(25+75)−25.12
=53.100−300=53.100−300
=5300−300=5300−300
=5000=5000.
b) 260:[5+7.(72:23−6)]−32260:[5+7.(72:23−6)]−32
=260:[5+7.(72:8−6)]−9=260:[5+7.(72:8−6)]−9
=260:[5+7.3]−9=260:[5+7.3]−9
=260:26−9=260:26−9
=10−9=10−9
=1=1.