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Dương Phương Linh
Giới thiệu về bản thân
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a) (\(\dfrac{1}{2}\)+ 1,5 ) . x = \(\dfrac{1}{5}\)
2x = \(\dfrac{1}{5}\)
x = \(\dfrac{1}{5}\) : 2
x = \(\dfrac{1}{10}\)
b) ( -1\(\dfrac{3}{5}\) + x ) : \(\dfrac{12}{13}\) = 2\(\dfrac{1}{6}\)
\(\dfrac{-8}{5}\) +x =\(\dfrac{13}{6}\) . \(\dfrac{12}{13}\)
\(\dfrac{-8}{5}\) + x = 2
x =\(\dfrac{-8}{5}\)- 2
x = \(\dfrac{-18}{5}\)
c) (x : 2\(\dfrac{1}{3}\) ) . \(\dfrac{1}{7}\) = \(\dfrac{-3}{8}\)
x : \(\dfrac{7}{3}\) = \(\dfrac{-3}{8}:\dfrac{1}{7}\)
x : \(\dfrac{7}{3}\) = \(\dfrac{-21}{8}\)
x = \(\dfrac{-21}{8}.\dfrac{7}{3}\)
x =\(\dfrac{-49}{8}\)
d) \(\dfrac{-4}{7}\)x +\(\dfrac{7}{5}\) = \(\dfrac{1}{8}\) : (-1\(\dfrac{2}{3}\))
\(\dfrac{-4}{7}\)x + \(\dfrac{7}{5}\) = \(\dfrac{-3}{40}\)
\(\dfrac{-4}{7}\)x = \(\dfrac{-3}{40}-\dfrac{7}{5}\)
\(\dfrac{-4}{7}\)x = \(\dfrac{-59}{40}\)
x =\(\dfrac{-59}{40}:\dfrac{-4}{7}\)
x = \(\dfrac{413}{160}\)
a) \(\dfrac{1}{2}\) - ( x + \(\dfrac{1}{3}\) ) = \(\dfrac{5}{6}\)
x + \(\dfrac{1}{3}\) = \(\dfrac{1}{2}\) - \(\dfrac{5}{6}\)
x + \(\dfrac{1}{3}\) = \(\dfrac{3}{6}\) - \(\dfrac{5}{6}\)
x + \(\dfrac{1}{3}\) = \(\dfrac{-2}{6}\)
x = \(\dfrac{-2}{6}\) - \(\dfrac{1}{3}\)
x = \(\dfrac{-1}{3}\) - \(\dfrac{1}{3}\)
x = \(\dfrac{-2}{3}\)
b) (\(\dfrac{3}{8}\) - \(\dfrac{1}{5}\)) + (\(\dfrac{5}{8}\) - x) = \(\dfrac{1}{5}\)
(\(\dfrac{15}{40}\) - \(\dfrac{8}{40}\))+ (\(\dfrac{5}{8}\) - x)= \(\dfrac{1}{5}\)
\(\dfrac{7}{40}\) + (\(\dfrac{5}{8}\) - x)= \(\dfrac{1}{5}\)
\(\dfrac{5}{8}\) - x = \(\dfrac{1}{5}-\dfrac{7}{40}\)
\(\dfrac{5}{8}\)- x =\(\dfrac{8}{40}-\dfrac{7}{40}\)
\(\dfrac{5}{8}\) - x = \(\dfrac{1}{40}\)
x = \(\dfrac{5}{8}\) - \(\dfrac{1}{40}\)
x = \(\dfrac{25}{40}-\dfrac{1}{40}\)
x = \(\dfrac{24}{40}\)
x = \(\dfrac{3}{5}\)
a) -1,62 + \(\dfrac{2}{5}\) + x = 7
\(\dfrac{2}{5}\) + x = 7- (-1,62 )
\(\dfrac{2}{5}\) + x = 8,62
x = 8,62 - \(\dfrac{2}{5}\)
x = \(\dfrac{431}{50}\) - \(\dfrac{20}{50}\)
x = \(\dfrac{411}{50}\)
b) 4\(\dfrac{3}{5}\) - x = \(\dfrac{-1}{5}\) +\(\dfrac{1}{2}\)
\(\dfrac{23}{5}\) - x = \(\dfrac{-2}{10}\) + \(\dfrac{5}{10}\)
\(\dfrac{23}{5}\) - x = \(\dfrac{3}{10}\)
x = \(\dfrac{23}{5}\) - \(\dfrac{3}{10}\)
x = \(\dfrac{46}{10}\) - \(\dfrac{3}{10}\)
x = \(\dfrac{43}{10}\)
c) \(\dfrac{-4}{7}\) -x = \(\dfrac{3}{5}\) -2x
-x + 2x = \(\dfrac{3}{5}\) + \(\dfrac{4}{7}\)
x = \(\dfrac{21}{35}\) + \(\dfrac{20}{35}\)
x = \(\dfrac{41}{35}\)
d) \(\dfrac{5}{7}\) - \(\dfrac{1}{13}\) + 0,25 = 3\(\dfrac{1}{2}\) - x
x = \(\dfrac{7}{2}\) - \(\dfrac{1}{4}\) + \(\dfrac{1}{13}\) - \(\dfrac{3}{7}\)
x = \(\dfrac{951}{364}\)