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2024-11-13 11:59:52
; (
x
+
1
x+1)(
x
2
x
2
- 4) = 0
[
x
+
1
=
0
x
2
−
4
=
0
[
x+1=0
x
2
−4=0
[
x
=
−
1
x
=
−
2
x
=
2
x=−1
x
=−2
x=2
Vậy
x
∈
x∈ {-1; -2; 2}
b; (
x
x - 2).(
x
2
x
2
+ 1) = 0
Vì
x
2
x
2
≥ 0 ∀
x
x;
x
x2 + 1 ≥ 1 > 0 ∀
x
x
⇒
x
−
2
x−2 = 0 ⇒
x
x = 2
Vậy
x
=
2
x=2
c; 13.(
x
−
5
x−5) = - 169
x
−
5
x−5 = 169 : 13
x
−
5
x−5 = -13
x
=
−
13
+
5
x=−13+5
Vậy
x
.
(
x
−
2
)
x.(x−2) = 0
[
x
=
0
x
−
2
=
0
[
x=0
x−2=0
[
x
=
0
x
=
2
[
x=0
x=2
Vậy
x
∈
x∈ {0; 2}