Nguyễn Xuân Nhật Đức
Giới thiệu về bản thân
Có: ∣\(\sqrt{x}\)-1∣-3=1
∣\(\sqrt{x}\)-1∣=4
_Nếu ∣\(\sqrt{x}\)-1∣=\(\sqrt{x}\)-1 thì:
\(\sqrt{x}\)-1=4
\(\sqrt{x}\)=5
x=\(5^2\)=25
_Nếu ∣\(\sqrt{x}\)-1∣=-(\(\sqrt{x}\)-1)=-\(\sqrt{x}\)+1 thì:
-\(\sqrt{x}\)+1=4
-\(\sqrt{x}\)=3
\(\sqrt{x}\)=-3
x=\(\left(-3\right)^2\)
x=9
Vậy x=25 hoặc x=9
Bài giải
Số tiền lãi là:
2062400-2000000=62400(đồng)
Lãi suất hàng tháng là:
62400:6=10400(đồng)
Đáp số: 10400 đồng
a)0,(3)+3\(\dfrac{1}{2}\)+0,4(2)=\(\dfrac{1}{3}\)+\(\dfrac{7}{2}\)+\(\dfrac{19}{45}\)=\(\dfrac{30}{90}\)+\(\dfrac{315}{90}\)+\(\dfrac{38}{90}\)=\(\dfrac{383}{90}\)
b)\(\dfrac{4}{9}\)+\(\dfrac{1219}{990}\)-\(\dfrac{13}{99}\)=\(\dfrac{440}{990}\)+\(\dfrac{1219}{990}\)-\(\dfrac{130}{990}\)=\(\dfrac{1529}{990}\)=\(\dfrac{139}{90}\)
a) Nếu x=0,5 thì:
A=\(0,5^2\)-2.\(0,5\)+3
A=0.5.(0,5-2)+3
A=0,5.(-1,5)+3
A=-0,75+3
A=2,25
Nếu x=-0,5 thì:
A=\(\left(-0,5\right)^2\)-2.\(\left(-0,5\right)\)+3
A=-0,5.(-0,5-2)+3
A=-0,5.(-2,5)+3
A=1,25+3
A=4,25
Vậy A=2,25 hoặc A=4,25
b) Nếu x=\(\dfrac{1}{3}\) thì:
B=\(\dfrac{1}{3}\)-3+1-3.\(\dfrac{1}{3}\)
B=\(\dfrac{1}{3}\).(1-3)-3+1
B=\(\dfrac{1}{3}\).(-2)-2
B=(-2).(\(\dfrac{1}{3}\)+1)
B=(-2).\(\dfrac{4}{3}\)
B=\(\dfrac{-8}{3}\)
Nếu x=\(\dfrac{-1}{3}\) thì:
B=\(\dfrac{-1}{3}\)-3+1-3.\(\dfrac{-1}{3}\)
B=\(\dfrac{-1}{3}\).(1-3)-3+1
B=\(\dfrac{-1}{3}\).(-2)-2
B=(\(\dfrac{-1}{3}\)+1).(-2)
B=\(\dfrac{2}{3}\)(-2)
B=\(\dfrac{-4}{3}\)
Vậy B=\(\dfrac{-8}{3}\) hoặc B=\(\dfrac{-4}{3}\)
a) Có: m=\(\sqrt{25+9}\)=\(\sqrt{34}\)=5,83095...
n=\(\sqrt{25}\)+\(\sqrt{9}\)=5+3=8
Vì 5,83095...<8 nên m<n
Vậy m<n
b) Có: y=\(\sqrt{49-16}\)=\(\sqrt{33}\)=5,744...
z=\(\sqrt{81}\)-\(\sqrt{9}\)=9-3=6
Vì 5,744...<6 nên y<z
Vậy y<z
a) A=\(\sqrt{36}\).3\(\sqrt{4}\)-\(\sqrt{\dfrac{1}{9}}\)+2
A=6.3.2-\(\dfrac{1}{3}\)+2
A=36-\(\dfrac{1}{3}\)+\(\dfrac{6}{3}\)
A=\(\dfrac{108}{3}\)-\(\dfrac{1}{3}\)+\(\dfrac{6}{3}\)
A=\(\dfrac{113}{3}\)
Vậy A=\(\dfrac{113}{3}\)
b) B=\(\sqrt{\dfrac{1}{9}+\dfrac{1}{16}}\)
B=\(\sqrt{\dfrac{25}{144}}\)
B=\(\dfrac{5}{12}\)
Vậy B=\(\dfrac{5}{12}\)
c) C=\(\sqrt{\dfrac{1}{9}}\)+\(\sqrt{\dfrac{25}{36}}\)-\(\sqrt{\dfrac{49}{81}}\):\(\sqrt{\dfrac{441}{324}}\)
C=\(\dfrac{1}{3}\)+\(\dfrac{5}{6}\)-\(\dfrac{7}{9}\):\(\dfrac{7}{6}\)
C=\(\dfrac{2}{6}\)+\(\dfrac{5}{6}\)-\(\dfrac{2}{3}\)
C=\(\dfrac{2}{6}\)+\(\dfrac{5}{6}\)-\(\dfrac{4}{6}\)
C=2
Vậy C=2
d) D=\(\sqrt{\left(\dfrac{-2}{5}\right)^2}\)+\(\sqrt{1,44}\)-\(\sqrt{256}\)
D=\(\dfrac{2}{5}\)+\(\dfrac{6}{5}\)-16
D=\(\dfrac{8}{5}\)-\(\dfrac{80}{5}\)
D=\(\dfrac{-75}{5}\)=-15
Vậy D=-15
Bài giải
Chu vi mảnh vườn là:
(5,5+3,75).2=18,5(m)
Số khóm hoa cần trồng là:
18,5:\(\dfrac{1}{4}\)=74(khóm)
Đáp số: 74 khóm hoa
a)\(\dfrac{1}{5}\)+\(\dfrac{4}{5}\):x=0,75
\(\dfrac{4}{5}\):x=0,75-\(\dfrac{1}{5}\)
\(\dfrac{4}{5}\):x=\(\dfrac{11}{20}\)
x=\(\dfrac{4}{5}\):\(\dfrac{11}{20}\)
x=\(\dfrac{16}{11}\)
Vậy x=\(\dfrac{16}{11}\)
b)x+\(\dfrac{1}{2}\)=1-x
x+x =1-\(\dfrac{1}{2}\)
2x=\(\dfrac{1}{2}\)
x=\(\dfrac{1}{2}\):2
x=\(\dfrac{1}{4}\)
Vậy x=\(\dfrac{1}{4}\)
a)\(\dfrac{2}{3}\).\(\dfrac{5}{4}\)-\(\dfrac{3}{4}\).\(\dfrac{2}{3}\)=\(\dfrac{2}{3}\).(\(\dfrac{5}{4}\)-\(\dfrac{3}{4}\))=\(\dfrac{2}{3}\).\(\dfrac{1}{2}\)=\(\dfrac{1}{3}\)
b)2.(\(\dfrac{-3}{2}\))\(^2\)-\(\dfrac{7}{2}\)=2.\(\dfrac{9}{4}\)-\(\dfrac{7}{2}\)=\(\dfrac{9}{2}\)-\(\dfrac{7}{2}\)=\(\dfrac{2}{2}\)=1
c)-\(\dfrac{3}{4}\).5\(\dfrac{3}{13}\)-0,75.\(\dfrac{36}{13}\)=\(\dfrac{-3}{4}\).\(\dfrac{68}{13}\)+\(\dfrac{-3}{4}\).\(\dfrac{36}{13}\)=\(\dfrac{-3}{4}\).(\(\dfrac{68}{13}\)+\(\dfrac{36}{13}\))=\(\dfrac{-3}{4}\).\(\dfrac{104}{13}\)=-6