Minh Tú sét boi
Giới thiệu về bản thân
\(Đề:góc\text{ }SIS=30\text{°}\)
\(Vẽ\text{ }pháp\text{ }tuyến\text{ }IN\perp qua\text{ }gương\text{ }phẳng\text{ }G\)
\(nên\text{ }góc\text{ }GIN=90\text{°}\)
\(ta\text{ }có:\text{ }góc\text{ }GIS+i'=góc\text{ }GIN=90\text{°}\)
\(\rightarrow i=90\text{°}-góc\text{ }\text{ }GIS\)
\(\rightarrow i=90\text{°}-30\text{°}=60\text{°}\)
\(Theo\text{ }định\text{ }luật\text{ }phản\text{ }xạ\text{ }ánh\text{ }sáng\text{ }thì:i'=i=60\text{°}\)
\(Đáp\text{ }số:góc\text{ }phản\text{ }xạ:60\text{°}.\)
\(1424\text{×}59+42\text{×}1424-1424\)
\(=1424\text{×}59+42\text{×}1424-1424\text{×}1\)
\(=1424\text{×}\left(59+42-1\right)\)
\(=1424\text{×}100=142400\)
\(69,4:0,1-69,4:0,125-69,4\)
\(=69,4\text{×}10-69,4\text{×}8-69,4\text{×}1\)
\(=69,4\text{×}\left(10-8-1\right)\)
\(=69,4\text{×}1=69,4\)
\(223+4315-175=4363\)
\(6438-235\text{×}2=5968\)
\(480-120:4=450\)
\(63+24\text{×}3=135\)
\(-Số\text{ }chia\text{ }hết\text{ }cho\text{ }2:5968;450.\)
\(-Số\text{ }chia\text{ }hết\text{ }cho\text{ }5:450;135.\)
\(3.\left(25:5-14:2\right)-5.\left(6:2\right)\)
\(=3.\left(5-7\right)-5.3\)
\(=3.\left(-2\right)-5.3\)
\(=-6-15=-21\)
\(=28,17\)