Em đăng kí tham gia khảo sát tiền thưởng của OLM ạ .

A

4 tấn 8taj = 4,8 tấn

18,97ha=0,1897 km²

2022.999+2022

=2022(999+1)

=2022.1000

=2022000

5.2²-18:3

=5.4-6

=20-6

=14

\(20,22x97+20,22:0,25-20,22\\ 20,22x97+20,22x4-20,11x1\\ =20,22x\left(97+4-1\right)\\ =20,22x100\\ =2022\)

\(20,22x97+20,22:0,25-20,22\\ 20,22x97+20,22x4-20,11x1\\ =20,22x\left(97+4-1\right)\\ =20,22x100\\ =2022\)

\(20,22x97+20,22:0,25-20,22\\ 20,22x97+20,22x4-20,11x1\\ =20,22x\left(97+4-1\right)\\ =20,22x100\\ =2022\)

\(xy-2x-y=2\\ \text{X}\left(y-2\right)-y=2\\ \text{X}\left(y-2\right)-\left(y-2\right)=2+2=4\\ \left(x-1\right)\left(y-2\right)=4\\ \Rightarrow y-2\in\text{Ư}\left(4\right)=\left\{\pm4;\pm2;\pm1\right\}\)

Lập bảng 

\(B=1+2^1+2^2+2^3+2^4+...+2^{100}\\ 2\text{B}=2^1+2^2+2^3+2^4+2^5+...+2^{101}\\ 2\text{B}-B=b=\left(2^1+2^2+2^3+2^4+2^5+...+2^{101}\right)-\left(1+2^1+2^2+2^3+2^4+...+2^{100}\right)\\ B=2^{101}-1\)

\(2n+3⋮n-2\\ 2\left(n-2\right)+7⋮n-2\\ =>7⋮n-2\\ =>n-2\in\text{Ư}\left(7\right)=\left\{-7;-1;1;7\right\}\\ =>n\in\left\{-5;1;3;9\right\}\)