Tính

C. \(\left(6^{2023}-6^{2023}\right):6^{2021}\)

\(=6^{2023}:6^{2021}-6^{2023}:6^{2021}\)

\(=6^2-6^2\)

\(=36-36\)

\(=0\)

$83\times 14+27\times 17+83\times 13$

$=83\times \left(14+13\right)+27\times 17$

$=83\times 27+27\times 17$

$=\left(83+17\right)\times 27$

$=100\times 27$

$=2700$

Chúc bạn học tốt

lck quá

$\genfrac{}{}{0ex}{}{1}{8}+\genfrac{}{}{0ex}{}{-3}{4}):\genfrac{}{}{0ex}{}{5}{6}+\genfrac{}{}{0ex}{}{1}{2}$

$=\left(\genfrac{}{}{0ex}{}{1}{8}+\genfrac{}{}{0ex}{}{-6}{8}\right)\times \genfrac{}{}{0ex}{}{6}{5}+\genfrac{}{}{0ex}{}{1}{2}$

$=\genfrac{}{}{0ex}{}{-5}{8}\times \genfrac{}{}{0ex}{}{6}{5}+\genfrac{}{}{0ex}{}{1}{2}$

$=\genfrac{}{}{0ex}{}{-3}{4}+\genfrac{}{}{0ex}{}{1}{2}$

$=\genfrac{}{}{0ex}{}{-3}{4}+\genfrac{}{}{0ex}{}{2}{4}$

$=\genfrac{}{}{0ex}{}{-1}{4}$

Chúc bạn học tốt

E= 5 + 52 +53 + 54 + ..... + 520 

E= 5+(2+5)+54+(2+5)+...+518+(2+5)

E = 5x7+54x7+...+518x7

E = 5x(5+54+...+518)

mà 7 chia hết 7 => 5x(5+54+...+518) chia hết 7

Vậy E chia hết cho 7

Xin lỗi nay não lack

Sory

Lick giùp

F = 5 + 52 ₊₅3 + 54 + ..... + 5²⁰ 

F= 5+(2+5)+5⁴+(2+5)+...+5¹⁸+(2+5)

F = 5x7+5⁴x7+...+5¹⁸x7

F= 5x(5+5⁴+...+5¹⁸)

mà 7 chia hết 7 => 5x(5+5⁴+...+5¹⁸) chia hết 7

Vậy F chia hết cho 8