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Nguyễn Thị Ngọc Anh
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2023-08-21 09:22:40
ΔfH298°=ΣΔfH298°(sp)−ΣΔfH298°(cđ)= 2.(-393,5) + 3.(-285,84) - (-84,7) = -1559,82 kJ.
2023-08-21 09:21:49
2023-08-21 09:20:21
a. PTHH 2KMnO4 + 16HClđặc ----> 2KCl + 2MnCl2 + 5Cl2 + 8H2O
Chất khử: HCl Chất oxi hóa: KMnO4
Quá trình oxi hóa: 2Cl- ---> Cl20 + 2e |x5
Quá trình khử: Mn+7 + 5e ---> Mn+2 |x2
b, nNaI = 0,2.0,1 = 0,02 (mol) PTHH: 2NaI + Cl2 ---> 2NaCl + I2
mol: 0,02 --> 0,01 => PTHH: 2KMnO4 + 16HClđặc ----> 2KCl + 2MnCl2 + 5Cl2 + 8H2O mol: 0,004 <--- 0,01 => mKMnO4 = n.M = 0,004.158 = 0,632(g)