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Nguyễn Gia Huy
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2024-04-15 20:52:24
phần trăm nguyên tử C là:
C%=(12.13)/(12.13+1.21+14+16.3).100%=15,06%
2024-04-15 20:50:36
2024-04-01 15:02:43
2024-04-01 14:50:36
a) MgO + 2HCl -> MgCl2 + H2O
0,05 0,1
MgCO3 + 2HCl -> MgCl2 + CO2 + H2O
0,1 0,2 0,1 0,1
b) nCO2 = 2,24/22,4 = 0,1 (mol)
Theo phương trình (1) ta có: nMgCO3 = nCO2 = 0,1 (mol)
Khối lượng MgCO3 là: mMgCO3 = 0,1 x 84 = 8,4 (g)
Khối lượng MgO là: mMgO = 10,4 - 8,4 = 2 (g)
2024-04-01 14:45:48
2024-04-01 14:38:33