199^20 và 2013^15
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a>\(16^{19}=2^{4^{19}}=2^{76}\\ 8^{25}=2^{3^{25}}=2^{75}\)
16^19>8^25
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\(199^{20}=39601^{19}\)
mà \(39601>2016\)và \(19>15\)\(\Rightarrow199^{20}>2016^{15}\)
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ta có:
\(199^{20}=\left(199^4\right)^5=1568239201^5\)
\(2003^{15}=\left(2003^3\right)^5=8036054027^5\)
vì \(1568239201>1\)
\(8036054027>1\)
\(1568239201< 8036054027\)
=>\(199^{20}< 2003^{15}\)
19920=(1994)5=15682392015
200315=(20033)5=80360540275
Vì 1568239201<8036054027
Vậy 19920 <200315
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Ta có:
19920 = (1994)5 < (2004)5
201715 = (20173)5 > (20003)5
Mà 1994 < 2004 < 20003 < 20173
=> 19920 < 201715
Ta có: \(199^{20}< 200^{20}\)
\(2017^{15}>2000^{15}\)
Lại có: \(200^{20}=\left(200^4\right)^5=\left(16.10^8\right)^5\)
\(2000^{15}=\left(2000^3\right)^5=\left(8.10^9\right)^5=\left(80.10^8\right)^5\)
Do \(16.10^8< 80.10^8\)
\(\Rightarrow200^{20}< 2000^{15}\)
\(\Rightarrow199^{20}< 2017^{15}\)
Ta có:
\(199^{20}< 200^{20}\)\(;\)\(2013^{15}>2000^{15}\)
Lại có: \(200^{20}=\left(200^4\right)^5=\left(16.10^8\right)^5\)
\(2000^{15}=\left(2000^3\right)^5=\left(8.10^9\right)^5=\left(80.10^8\right)^5\)
Do \(16.10^8< 80.10^8\)
\(\Rightarrow200^{20}< 2000^{15}\)
\(\Rightarrow199^{20}< 2013^{15}\)
Tự làm đê