rút gon các bt sau B=(3x+1)^2-2(3x+1)(2-5x)+(15x+x)^2
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
25 tháng 8 2016
a) 5x2 ( 3x2 -7x+2)-15x(x-3)
=15x4-35x3+10x2-15x2+45x
=15x4-35x3-5x2+45x
c) (x+3)(x-3)(x-2)(x+1)
=(x2-9)(x2+x-2x-2)
=(x2-9)(x2-x-2)
=x4-x3-2x2-9x2+9x+18
=x4-x3-11x2+9x+18
d)(2x+1)2+(4x-1)2+2(2x+1)(4x+1)
=2x2+4x+1-16x2-8x+1
=2x2+4x+1-16x2-8x+1+16x2-4x+8x-2
=2x2+7
e) (2x2-3x)(5x2-2x+1)-10x2(x+3)
=10x4 -4x3+2x2-15x3+6x2-3 -10x2-30x
=10x4-19x3-2x2-30x-3
21 tháng 9 2015
Như sau :
\(D=\frac{\left(x+2\right)\left(x+3\right)+x\sqrt{\left(3-x\right)\left(3+x\right)}}{x\left(3-x\right)+\left(x+2\right)\sqrt{\left(3-x\right)\left(3+x\right)}}=\frac{\sqrt{x+3}\left[\left(x+2\right)\sqrt{x+3}+x\sqrt{3-x}\right]}{\sqrt{3-x}\left(x\sqrt{3-x}+\left(x+2\right)\sqrt{3+x}\right)}=\frac{\sqrt{x+3}}{\sqrt{3-x}}\)
NH
1
18 tháng 10 2023
a) \(\left(3x-2\right)^2-\left(2x+3\right)\left(2x-3\right)\)
\(=9x^2-12x+4-4x^2+9\)
\(=5x^2-12x+13\)
b) \(3x\left(5x-2\right)-\left(2x^2-1\right)\left(2-x\right)\)
\(=15x^2-6x-\left(4x^2-2x^3-2+x\right)\)
\(=15x^2-6x-4x^2+2x^3+2-x\)
\(=11x^2-7x+2x^3+2\)
PT
21 tháng 7 2021
a/ 2x\(^{^{ }3}\)-3\(^{^{ }3}\)-2x\(^3\)-1\(^{^{ }3}\)=-28
b/x\(^{^{ }3}\)+2\(^{^{ }3}\)-x\(^3\)+2=10
c/3x\(^3\)+5\(^3\)-3x(3x\(^2\)-1)=3x\(^3\)+5\(^3\)-3x\(^3\)+3x=125+3x
d/ x\(^6\)-(x\(^3\)+1)(x\(^2\)-x+1)= x\(^6\)-(x\(^6\)-x\(^4\)+x\(^3\)+x\(^2\)-x+1)=x\(^4\)-x\(^3\)-x\(^2\)+x-1
AN
28 tháng 9 2017
phan tich cac da thuc sau thanh nhan tu theo mau:
a)\(2x^3-x\)
\(=x\left(2x^2-1\right)\)
\(=x\left(\left(\sqrt{2}x\right)^2-1^2\right)\)\
\(=x\left(\sqrt{2}x-1\right)\left(\sqrt{2}x+1\right)\)
b)\(5x^2\left(x-1\right)-15x\left(x-1\right)\)
\(=\left(5x^2-15x\right)\left(x-1\right)\)
\(=5x\left(x-3\right)\left(x-1\right)\)
d)\(3x\left(x-2y\right)+6y\left(2y-x\right)\)
\(=3x\left(x-2y\right)-6y\left(x-2y\right)\)
\(=\left(3x-6y\right)\left(x-2y\right)\)
\(=3\left(x-2y\right)\left(x-2y\right)\)
\(=3\left(x-2y\right)^2\)
hallo
\(=\left(\right.3x+1\left.\right)^2-2\left(\right.3x+1\left.\right)\left(\right.2-5x\left.\right)+256x^2\)
\(=\left(9x^2+6x+1\right)-\left(6x+2\right)\left(2-5x\right)+16x^2\)\(=\left(9x^2+6x+1\right)\) \(-\left(12x-30x^2+4-10x\right)+256x^2\)
\(=9x^2+6x+1-12x+30x^2-4+10x+256x^2\)
\(=295x^2+4x-3\)