B=1/7*(555/222+4444/12221+33333/244442+11/330+13/60)
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B=1/7.(555/222+4444/1221+33333/244442+11/330+13/60
B= 1/7.(5/2+4/11+3/22+11/330+13/60)
B= 1/7.(1650/660+240/660+90/660+22/660+143/660)
B=1/7.143/44
B=143/308
k mk nha, k xong bình luận bên dưới mk k lại cho

a: \(\left(-1\right)\left(-1\right)^2\cdot\left(-1\right)^3\cdot\ldots\cdot\left(-1\right)^{2014}\)
\(=\left(-1\right)^{1+2+\cdots+2014}\)
\(=\left(-1\right)^{2014\cdot\frac{2015}{2}}=\left(-1\right)^{1007\cdot2015}=-1\)
b: \(\frac17\left(\frac{555}{222}+\frac{4444}{12221}+\frac{33333}{244442}+\frac{11}{130}+\frac{13}{60}\right)\)
\(=\frac17\left(\frac52+\frac{4}{11}+\frac{3}{22}+\frac{11}{130}+\frac{13}{60}\right)\)
\(=\frac17\left(3+\frac{13}{60}+\frac{11}{130}\right)=\frac17\cdot\frac{515}{156}=\frac{515}{1092}\)

\(A=\dfrac{1}{7}\left(\dfrac{555}{777}+\dfrac{4444}{12221}+\dfrac{33333}{244442}+\dfrac{11}{30}+\dfrac{13}{30}\right)\)
\(=\dfrac{1}{7}\left(\dfrac{5}{7}+\dfrac{4}{11}+\dfrac{3}{22}+\dfrac{23}{30}\right)\\ =\dfrac{1}{7}\left(\dfrac{5}{7}+\dfrac{1}{2}+\dfrac{23}{30}\right)\\ =\dfrac{1}{7}\cdot\dfrac{208}{105}\\ =\dfrac{208}{735}\)
\(B=\frac{1}{7}\left(\frac{5}{2}+\frac{4}{11}+\frac{3}{22}+\frac{11}{30}+\frac{13}{60}\right)\)
\(B=\frac{1}{7}\left(\frac{5}{2}+\frac{11}{22}+\frac{35}{60}\right)\)
quy đồng tính nốt ra \(B=\frac{43}{84}\)
Nhớ bấm L I K E cho mk nhá :))))