2+3-2+1-1+2+3:8.9=....
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11 tháng 7 2023
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{2^8-2^3}{2^5-1}=\dfrac{2^3\left(2^5-1\right)}{2^5-1}=\dfrac{2^3}{1}=2^3=8\)
_____
\(\dfrac{4^8\cdot9^4}{6^6\cdot8^3}\)
`=`\(\dfrac{\left(2^2\right)^8\cdot\left(3^2\right)^4}{2^6\cdot3^6\cdot\left(2^3\right)^3}\)
`=`\(\dfrac{2^{16}\cdot3^8}{2^6\cdot3^6\cdot2^9}\)
`=`\(\dfrac{2^{16}\cdot3^8}{2^{15}\cdot3^6}\)
`=`\(\dfrac{3^2}{2}\) `=`\(\dfrac{9}{2}\)
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\(\dfrac{27^4\cdot2^3-3^{10}\cdot4^3}{6^4\cdot9^3}\)
`=`\(\dfrac{\left(3^3\right)^4\cdot2^3-3^{10}\cdot\left(2^2\right)^3}{2^4\cdot3^4\cdot\left(3^2\right)^3}\)
`=`\(\dfrac{3^{12}\cdot2^3-3^{10}\cdot2^6}{2^4\cdot3^4\cdot3^6}\)
`=`\(\dfrac{3^{10}\cdot\left(3^2\cdot2^3-2^6\right)}{3^{10}\cdot2^4}\)
`=`\(\dfrac{72-2^6}{2^4}=\dfrac{8}{16}=\dfrac{1}{2}\)
11 tháng 7 2023
\(\dfrac{2^8-2^3}{2^5-1}=\dfrac{2^3\left(2^5-1\right)}{2^5-1}=2^3=8\)
\(\dfrac{4^8.9^4}{6^6.8^3}=\dfrac{2^{16}.3^8}{2^6.3^6.2^9}=2.3^2=18\)
\(\dfrac{27^4.2^3-3^{10}.4^3}{6^4.9^3}=\dfrac{3^{12}.2^3-3^{10}.2^6}{2^4.3^4.3^6}=\dfrac{2^3.3^{10}.\left(3^2-2^3\right)}{2^4.3^{10}}=\dfrac{9-8}{2}=\dfrac{1}{2}\)
16 tháng 9 2018
a) Có \(\dfrac{2^8.9^2}{6^4.8^2}\)=\(\dfrac{2^8.3^4}{3^4.2^42^6}\)=\(\dfrac{2^8.3^4}{3^4.2^{10}}\)=\(\dfrac{2^8}{2^{10}}\)=\(\dfrac{1}{4}\)
b) Có \(\left(2^{-1}+3^{-1}\right):\left(2^{-1}-3^{-1}\right)+\left(2^{-1}.2^0\right).2^3\)
= \(\dfrac{2^{-1}+3^{-1}}{2^{-1}-3^{-1}}+2^{-1}.2^3\)
=\(\dfrac{\dfrac{1}{2}+\dfrac{1}{3}}{\dfrac{1}{2}-\dfrac{1}{3}}+\dfrac{1}{2}.2^3\)
= \(\dfrac{\dfrac{5}{6}}{\dfrac{1}{6}}+2^2\)=5+8=13
6 tháng 4 2021
3.(1/4.5+1/5.6+...+1/9.10).x=9/2
3.(1/4-1/5+1/5-1/6+...+1/9-1/10).x=9/2
3.(1/4-1/10).x=9/2
3.3/20.x=9/2
9/20.x=9/2
x=9/2:9/20
x=10
HM
1
5 tháng 10 2015
\(\frac{5.6^{13}.2^3+4^8.9^6}{6.2^{15}.3^{12}}=\frac{5.3^{13}.2^{13}.2^3+2^{16}.3^{12}}{2.3.2^{15}.3^{12}}=\frac{5.3^{13}.2^{16}+2^{16}.3^{12}}{2^{16}.3^{13}}=\frac{2^{16}.3^{12}.\left(5.3+1\right)}{2^{16}.3^{12}.3}=\frac{5.3+1}{3}=\frac{16}{3}\)
MT
5 tháng 8 2018
Ta có: \(B=\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}\)
\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(=\frac{1}{3}-\frac{1}{8}\)
\(=\frac{5}{24}\)
Vậy \(B=\frac{5}{24}\)
MT
5 tháng 8 2018
Ta có: \(C=\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}\)
\(=\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\)
\(=\frac{1}{4}-\frac{1}{9}\)
\(=\frac{5}{36}\)
Vậy \(C=\frac{5}{36}\)
D
2
27 tháng 2 2021
a) Ta có: \(\dfrac{8\cdot9-4\cdot15}{12\cdot7-180}\)
\(=\dfrac{4\cdot18-4\cdot15}{12\cdot7-12\cdot15}\)
\(=\dfrac{4\cdot\left(18-15\right)}{12\cdot\left(7-15\right)}\)
\(=\dfrac{4\cdot3}{12\cdot\left(-8\right)}\)
\(=\dfrac{12}{12\cdot\left(-8\right)}=\dfrac{-1}{8}\)
b) Ta có: \(\dfrac{2^3\cdot3}{2^2\cdot3^2\cdot5}\)
\(=\dfrac{2^2\cdot2\cdot3}{2^2\cdot3\cdot3\cdot5}\)
\(=\dfrac{2}{3\cdot5}=\dfrac{2}{15}\)
HD
27 tháng 2 2021
a)8⋅9−4⋅1512⋅7−1808⋅9−4⋅1512⋅7−180=4⋅18−4⋅1512⋅7−12⋅15=4⋅18−4⋅1512⋅7−12⋅15=4⋅(18−15)12⋅(7−15)=4⋅(18−15)12⋅(7−15)=4⋅312⋅(−8)=4⋅312⋅(−8)=1212⋅(−8)=−18=1212⋅(−8)=−18
b)23⋅322⋅32⋅523⋅322⋅32⋅5=2
nhấn máy tính là ra