Yx5-25x5=125000x1/4
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\(\frac{9}{4}-y.\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{9}{4}-y.\frac{5}{6}=\frac{5}{6}\)
\(y.\frac{5}{6}=\frac{9}{4}-\frac{5}{6}\)
\(y.\frac{5}{6}=\frac{17}{12}\)
\(y=\frac{17}{12}:\frac{5}{6}\)
\(y=\frac{17}{10}\)
\(\frac{9}{4}\)- y x \(\frac{5}{6}\)= \(\frac{1}{2}\)+ \(\frac{2}{3}\) = \(\frac{9}{4}\)- \(\frac{1}{2}\)- \(\frac{2}{3}\)= y x \(\frac{5}{6}\)
y x \(\frac{5}{6}\)= \(\frac{13}{12}\)
y = \(\frac{13}{12}\)x \(\frac{6}{5}\)= \(\frac{13}{10}\)
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y x 5 + (2 + 4 + 6 +...+ 18) = 270
=> y x 5 + (18 + 2) x 9 : 2 = 270 (Công thức tính tổng)
=> y x 5 + 20 x 9 : 2 = 270
=> y x 5 + 180 : 2 = 270
=> y x 5 + 90 = 270
=> y x 5 = 270 - 90
=> y x 5 = 180
=> y = 180 : 5
=> y = 36
Vậy...
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\(\left(y-5\right)-\left(y-5\right)+y\cdot5-y:5=5\)
=>\(5y-0,2y=5\)
=>4,8y=5
=>\(y=\dfrac{25}{24}\)
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y.5 + y : 1/2 + y : 1/3
= y.5 + y.2 + y.3
= y.(5 + 2 + 3)
= y.10
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\(y\text{×}5+y:0,25=81\)
\(y\text{×}5+y\text{×}4=81\)
\(y\text{×}\left(5+4\right)=81\)
\(y\text{×}9=81\)
\(y=81:9\)
\(y=9\)
\(y\text{×}3+y:0,2=64\)
\(y\text{×}3+y\text{×}5=64\)
\(y\text{×}\left(3+5\right)=64\)
\(y\text{×}8=64\)
\(y=64:8\)
\(y=8\)
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y * 1 + y * 2 + y * 3 + y * 4 + y *1 = 825
y * ( 1 + 2 + 3 + 4 + 1) =825
y * 11 = 825
y = 825 / 11
y = 75
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3xz=y*x5
=>3z=5y
=>z/5=y/3
x/3=y/4 =>x/9=y/12
y/3=z/5 =>y/12=z/20
=>x/9=y/12=z/20
Áp dụng tính chất của DTSBN, ta được:
\(\dfrac{x}{9}=\dfrac{y}{12}=\dfrac{z}{20}=\dfrac{2x-3y+z}{2\cdot9-3\cdot12+20}=\dfrac{6}{2}=3\)
=>x=18; y=36; z=60
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y x 5 - 25 x 5 = 125000 x \(\frac14\)
y x 5 - 125 = 31250
y x 5 = 31250 + 125
y x 5 = 31375
y = 31375 : 5
y = 6275
`y xx 5 - 25xx5 = 125000 xx 1/4`
`=> y xx 5 - 125 = 31250`
`=> y xx 5 = 31250 + 125`
`=> y xx 5 = 31375`
`=> y = 31375 :5`
`=> y = 6275`
Vậy `y = 6275`