tìm x:
112-12 .(x+1) =40
(3 .x -6). 2=0
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 2:
a: =>x-45=-20
hay x=25
b: =>35+30-5x=-12+112
=>65-5x=100
=>5x=-35
hay x=-7
c: =>x-124=1000
hay x=1124
d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)
\(\Leftrightarrow\left(3x-2\right)^3=64\)
=>3x-2=4
hay x=2
Bài 2:
a: =>x-45=-20
hay x=25
b: =>35+30-5x=-12+112=100
=>65-5x=100
=>5x=-35
hay x=-7
c: =>x-124=1000
hay x=1124
d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)
\(\Leftrightarrow\left(3x-2\right)^3=64\)
=>3x-2=4
hay x=2
a;(18 - 9 x 2)x (2+ 4 + 6 + 8 + 10)
= (18 - 18)x (2+ 4 + 6+ 8 +10)
= 0 x (2+ 4+ 6+ 8 + 10)
= 0
b; (7 x 8 -56): (2+ 4 + 6 +8 + 112)
= (56 - 56) : (2 +4 +6+ 8+ 112)
= 0 : (2 + 4+ 6 + 8+ 112)
= 0
c; (2 + 125 + 6 + 145 + 112) x (42 - 6 x 7)
= (2+ 125+ 6 + 145+ 112) x (42 - 42)
= (2 + 125+ 6 + 145+ 112) x 0
= 0
Câu d:
(12 x 6 - 12 x 4 - 12 x 2) x (347 + 125)
= 12x(6 - 4 -2) x (347 + 125)
= 12 x (2 - 2) x (347 + 125)
= 12 x 0 x (347 + 125)
= 0 x (347 + 125)
= 0
e: =>-40+3+33+40-x=47
=>36-x=47
=>x=-11
f: =>x(x-3)(11-x)(11+x)=0
hay \(x\in\left\{0;3;11;-11\right\}\)
g: =>-62-38-x+2x=-100
=>x-100=-100
hay x=0
i: =>x-12-2x-31=6
=>-x-43=6
=>x+43=-6
hay x=-49
h: =>(x+1)=0
=>x=-1
f: =>x(x-3)(x+11)(x-11)=0
hay \(x\in\left\{0;3;-11;11\right\}\)
112-12 .(x+1) =40
112 - 12x - 12 = 40
-12x = 40-100
12x = 60
x=5
(3x-6).2=0
=>3(x-2)=0
=>x-2 = 0 => x= 2
112-12.(x+1) =40 (3.x-6).2=0
12.(x-1) =112-40 (3.x-6)=0.2
12.(x-1)=72 (3.x-6)=0
(x-1)=72:12 3.x=0+6
(x-1)=6 3.x=6
x=6+1 x=6:3
x=7 x=3