So sánh 6^200 và 2^500
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a.
\(3^{200}=\left(3^2\right)^{100}=9^{100}>8^{100}=\left(2^3\right)^{100}=2^{300}\)
Vậy \(3^{200}>2^{300}\)
b.
\(5^{200}=\left(5^2\right)^{100}=25^{100}< 32^{100}=\left(2^5\right)^{100}=2^{500}\)
Vậy \(5^{200}< 2^{500}\)
Ta có : \(3^{200}=3^{2.100}=\left(3^2\right)^{100}=9^{100}\)
\(2^{300}=2^{3.100}=\left(2^3\right)^{100}=8^{100}\)
\(\Rightarrow9^{100}>8^{100}\)
\(\Rightarrow3^{200}>2^{300}\)
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\(\dfrac{1}{2^{500}}=\dfrac{1}{\left(2^5\right)^{100}}=\dfrac{1}{32^{100}}\\ \dfrac{1}{5^{200}}=\dfrac{1}{\left(5^2\right)^{100}}=\dfrac{1}{25^{100}}\)
mà `32^(100)>25^(100)`
nên \(\dfrac{1}{2^{500}}>\dfrac{1}{5^{200}}\)
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2500=(25)100=32100
5200=(52)100=25100
Vì 32100>25100nên 2500>5200
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5200=(52)100=25100.
2500=(25)100=32100.
Vì 25 < 32 => 25100<32100=>5200<2500
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a) Ta có: 2500 = (25)100 = 32100
5200= (52)100= 25100
Vì 32100>25100 => 2500 > 5200
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\(2^{500}=\left(2^5\right)^{100}=32^{100}\)
\(5^{200}=\left(5^2\right)^{100}=25^{100}\)
Vì \(32^{100}>25^{100}\)nên \(2^{500}>5^{200}\)
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2500 = (25) 100 = 32 100
5200 = (52)100 = 25100
Vì 32 > 25 nên 32100 > 25100
Vậy A > B
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Ta có:
\(6^{200}=6^{2.100}=\left(6^2\right)^{100}=36^{100}\)
\(2^{500}=2^{5.100}=\left(2^5\right)^{100}=32^{100}\)
Vì \(36>32\) nên \(36^{100}>32^{100}\)
Vậy \(6^{200}>2^{500}\)
\(#Wendy.Dang\)