x x 2.5 = 5000
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ta thấy 5010 lon hơn 5000 10 don vị. 10 đơn vị đó tương ứng với 5000x10= 50000.
mà phép tính B chỉ lớn hơn 600 lớn hơn 500 1 đơn vị. suy ra pháp tính B nhỏ hơn phép tính A
A=5000×5010+500
A=5000×5000+5000×10+500
=>5000×5000=5000×5000
5000×10+500 > 600
=> A > B
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5000 + 100 = 5100
7400 - 400 = 7000
2000 3 + 600 = 6600
8000 : 2 + 2000 = 6000
6000 - (5000 - 1000) = 2000
6000 - 5000 + 1000 = 2000
7000 - 3000 x 2 = 1000
(7000 - 3000) x 2 = 8000
5000 + 100 = 5100
7400 - 400 = 7000
2000 3 + 600 = 6600
8000 : 2 + 2000 = 6000
6000 - (5000 - 1000) = 2000
6000 - 5000 + 1000 = 2000
7000 - 3000 x 2 = 1000
(7000 - 3000) x 2 = 8000
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`a)x^3=343=7^3`
`=>x=7`
Vậy `x=7`
`b)(x-2,5)^4=(x-2,5)^2`
`=>(x-2,5)^2[(x-2,5)^2-1]=0`
`+)(x-2,5)^2=0<=>x=2,5`
`+)(x-2,5)^2=1`
`TH1:x-2,5=1<=>x=3,5`
`th2:x-2,5=-1<=>x=1,5`
Vậy `x=0` hoặc `x=1,5` hoặc `x=3,5
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x + 1000 = 5000 + 5000
x + 1000 = 10000
x = 10000 - 1000
x = 9000
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x + 2000 = 5000 + 5000
x + 2000 = 10000
x = 10000 - 2000
x = 8000
Vậy x = 8000
x + 2000 = 5000 + 5000
x + 2000 = 10000
x = 10000 - 2000
x = 8000
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x+3000=5000
x=5000-3000
x=2000
x-5000=3000
x=3000+5000
x=8000
x + 3000 = 5000
x = 5000 - 3000
x = 2000
x - 5000 = 3000
x = 3000 + 5000
x = 8000
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đặt x^1000=m,y^1000=n
m+n=a
m2+n2=2b/3 =>a2=2b/3+2mn =>mn=a2-2b/3
m5+n5=c/36 <=>(n+m)[(m+n)4-5mn(m+n)2+5m2n2]=c/36
<=>a.[a4-5(a2-2b/3)a2+5(a2-2b/3)2 ]=c/36 <=>a(a4-10a2b/3+20b2/9)=c/36 <=>a(9a4-30a2b+20b2)=c/4
x x 2.5 = 5000
x = 5000 : 2.5
x = 2000
x=5000:2,5
=>x=2000
vậy x=2000
ai nha