6. tính thuận tiện d) 5,8 + 5.8 x 3 + 5.8 x 5 + 5.8
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
tính như bình thường nha bạn. Có những câu đề bài là tính thuận tiện mà tính thường mk đã gặp nhiều rồi
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1/5.8+1/8.11+....+1/x(x+3)=1/6
=> 3/5.8 + 3/8.11 +.....+ 3/x(x+3)=1/2
=> 1/5-1/x+3=1/2
=> 1/x+3=1/5-1/2=-3/10=1/-10/3
=>x+3=-10/3=>x=-19/3
\(\frac{1}{5\cdot8}+\frac{1}{8\cdot11}+...+\frac{1}{x\left(x+3\right)}=\frac{1}{6}\)
\(\frac{3}{5\cdot8}+\frac{3}{8\cdot11}+...+\frac{3}{x\cdot\left(x+3\right)}=\frac{1}{2}\)
\(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+....+\frac{1}{x}-\frac{1}{x+3}=\frac{1}{2}\)
\(\frac{1}{5}-\frac{1}{x+3}=\frac{1}{2}\)
\(\frac{1}{x+3}=\frac{-3}{10}\)
\(\Rightarrow\left(-3\right)\left(x+3\right)=10\)
\(\Rightarrow x+3=\frac{-10}{3}\)
\(\Rightarrow x=\frac{-19}{3}\)
Vậy \(x=\frac{-19}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)2/13 . 5 - 9/11 . 2/13 - 7/11 . 2/13
=2/13.(5-9/11-7/11)
=2/13.39/11
=6/11.
b)(-1/2)2 + 4,25
=1/4+4,25
=1/4+17/4
=9/2.
c)(-2/3)2 : ( --2 2/3) -- ( 5/8 -- 5/6 ) + 5.8--45/5.8
= -4/3 : -8/3 - -5/24 + 40 - 72
= -751/24.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x-3\right)^2+\frac{-9}{25}=\frac{2}{5}.\frac{8}{5}\)
\(\left(x-3\right)^2+\frac{-9}{25}=\frac{16}{25}\)
\(\left(x-3\right)^2=\frac{16}{25}+\frac{-9}{25}\)
\(\left(x-3\right)^2=\frac{7}{25}\)
\(\left(x-3\right)^2=\left(\frac{7}{5}\right)^2\)
\(\Rightarrow x-3=\frac{7}{5}\)
\(\Rightarrow x=\frac{7}{5}+3\)
\(\Rightarrow x=\frac{22}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(D=\dfrac{2}{3}.\dfrac{5}{5.8}+\dfrac{11}{8.19}+\dfrac{13}{19.32}\)
\(D=\dfrac{2.5}{2.5.8}+\dfrac{1}{19}.\dfrac{11}{8}+\dfrac{1}{19}.\dfrac{13}{32}\)
\(D=\dfrac{1}{12}+\dfrac{1}{19}.\left(\dfrac{11}{8}+\dfrac{13}{32}\right)\)
\(D=\dfrac{1}{12}+\dfrac{1}{19}.\left(\dfrac{44}{32}+\dfrac{13}{32}\right)\)
\(D=\dfrac{1}{12}+\dfrac{1}{19}.\dfrac{57}{32}\)
\(D=\dfrac{1}{12}+\dfrac{3}{32}\)
\(D=\dfrac{8}{96}+\dfrac{9}{96}\)
\(D=\dfrac{17}{96}\)
=5,8(1+3+5+1)=58
=5.8 x (3+5)
=5.8 x 8
=29