Cl2→NaCl→AgCl
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a. NaCl → Cl2 → FeCl3 → NaCl → HCl → CuCl2 → AgCl.
2NaCl+2H2O-đp\mn->2NaOH+H2+Cl2
3Cl2+2Fe-to>2FeCl3
FeCl3+3NaOH->3NaCl+Fe(OH)3
2NaCl+H2SO4-to>Na2SO4+2HCl
2HCl+CuO->CuCl2+H2O
CuCl2+2AgNO3->2AgCl+Cu(NO3)2

a)
\(4HCl+MnO_2\rightarrow MnCl_2+Cl_2+2H_2O\)
\(2Fe+3Cl_2\rightarrow2FeCl_3\)
\(FeCl_3+3NaOH\rightarrow3NaCl+Fe\left(OH\right)_3\)
\(NaCl+AgNO_3\rightarrow NaNO_3+AgCl\)
b)
\(2KMnO_4+16HCl\rightarrow2KCl+2MnCl2+5Cl_2+8H_2O\)
\(Cl_2+H_2\rightarrow2HCl\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(2FeCl_2+Cl_2\rightarrow2FeCl_3\)
\(FeCl_3+3AgNO_3\rightarrow Fe\left(NO_3\right)_3+3AgCl\)
\(2AgCl\rightarrow2Ag+Cl_2\)
\(Cl_2+2NaBr\rightarrow2NaCl+Br_2\)

Br2 + 2KClO3 \(\xrightarrow[]{t^o}\) 2KBrO3 + Cl2
Fe + Cl2 \(\xrightarrow[]{t^o}\) FeCl3
3NaOH + FeCl3 \(\rightarrow\) 3NaCl + Fe(OH)3
NaCl + H2SO4 \(\rightarrow\) NaHSO4 + HCl
CuO + 2HCl \(\rightarrow\) CuCl2 + H2O
2AgNO3 + CuCl2\(\xrightarrow[]{t^o}\) 2AgCl + Cu(NO3)2

\(MnO_2+4HCl_{đặc,nóng}\rightarrow MnCl_2+Cl_2+2H_2O\\ H_2+Cl_2\rightarrow\left(t^o\right)2HCl\\ NaOH+HCl\rightarrow NaCl+H_2O\\ 2NaCl\rightarrow\left(đpnc\right)2Na+Cl_2\\ 2Al+3Cl_2\rightarrow\left(t^o\right)2AlCl_3\\ AlCl_3+3KOH\rightarrow Al\left(OH\right)_3\downarrow+3KCl\\ Al\left(OH\right)_3+3HCl\rightarrow AlCl_3+3H_2o\\ AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\downarrow\)
\(MnO_2\underrightarrow{1}Cl\underrightarrow{2}HCl\underrightarrow{3}NaCl\underrightarrow{4}Cl_2\underrightarrow{5}AlCl_3\underrightarrow{6}Al\left(OH\right)_3\underrightarrow{7}AlCl_3\underrightarrow{8}AgCl\)
(1) \(MnO_2+4HCl_{đặc}\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)
(2) \(H_2+Cl_2\xrightarrow[ánh.sáng]{t^o}2HCl\)
(3) \(NaOH+HCl\rightarrow NaCl+H_2O\)
(4) \(2NaCl+2H_2O\xrightarrow[có.màng.ngăn]{điện.phân}2NaOH+H_2+Cl_2\)
(5) \(2Al+3Cl_2\underrightarrow{t^o}2AlCl_3\)
(6) \(AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\)
(7) \(Al\left(OH\right)_3+3HCl\rightarrow AlCl_3+3H_2O\)
(8) \(AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\)
Chúc bạn học tốt

1,
\(4HCl+MnO_2\rightarrow MnCl_2+2H_2O+Cl_2\\ 2Fe+3Cl_2\underrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3\downarrow+3NaCl\\ 2NaCl+H_2SO_4\rightarrow Na_2SO_4+2HCl\uparrow\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2+2AgNO_3\rightarrow2AgCl\downarrow+Cu\left(NO_3\right)_2\)
2,
\(2KMnO_4+16HCl\rightarrow2KCl+8H_2O+5Cl_2+2MnCl_2\\ Cl_2+H_2\underrightarrow{as}2HCl\\ 6HCl+Fe_2O_3\rightarrow2FeCl_3+3H_2O\\ FeCl_3+3AgNO_3\rightarrow3AgCl\downarrow+Fe\left(NO_3\right)_3\\ 2AgCl\underrightarrow{as}2Ag+Cl_2\\ Cl_2+2NaBr\rightarrow2NaCl+Br_2\\ Br_2+2NaI\rightarrow2NaBr+I_2\)
3,
2 pthh đầu giống ở 2
\(Fe+2HCl\rightarrow FeCl_2+H_2\\ FeCl_2+2AgNO_3\rightarrow2AgCl\downarrow+Fe\left(NO_3\right)_2\\ 2AgCl\underrightarrow{as}2Ag+Cl_2\)
4, 2 pthh đầu gióng ở 1
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3\downarrow+3NaCl\\ 2Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O\)

(1) 2KMnO4 =nhiệt độ=> K2MnO4 + MnO2 + O2
(2) O2 + 4Fe(OH)2 =nhiệt độ=> 2Fe2O3 + 4H2O
(3) Fe2O3 + 6HCl => 2FeCl3 + 3H2O
(4) FeCl3 + 3NaOH => Fe(OH)3 + 3NaCl
(5) 2KMnO4 + 16HCl => 2KCl + 2MnCl2 + 5Cl2 + 8H2O
(6) Cl2 + 2Na =nhiệt độ=> 2NaCl
(7) NaCl + AgNO3 => AgCl + NaNO3
(8) 2AgCl =nhiệt độ=> 2Ag + Cl2

$a) MnO_2 + 4HCl \xrightarrow{t^o} MnCl_2 + Cl_2 + 2H_2O$
$Cl_2 + Cu \xrightarrow{t^o} CuCl_2$
$CuCl_2 + 2NaOH \to Cu(OH)_2 + 2NaCl$
$2NaCl + 2H_2O \xrightarrow{đpdd, cmn} 2NaOH + H_2 + Cl_2$
$2NaOH + Cl_2 \to NaCl + NaClO + H_2O$
$NaClO + HCl \to NaCl + HClO$
b)
$2KMnO_4 + 16HCl \to 2KCl + 2MnCl_2 + 5Cl_2 + 8H_2O$
$Cl_2 + H_2 \xrightarrow{ánh\ sáng} 2HCl$
$HCl + KOH \to KCl + H_2O$
$2KCl + 2H_2O \xrightarrow{đpdd, cmn} 2KOH + H_2 + Cl_2$
$3Cl_2 + 2Fe \xrightarrow{t^o} 2FeCl_3$
$FeCl_3 + 3AgNO_3 \to Fe(NO_3)_3 + 3AgCl$

2) 2KMnO4 + 16HCl = 2KCl + 2MnCl2 + 5Cl2 + 8H2O
Cl2 + H2 = 2HCl ( điều kiện ánh sáng )
2HCl + Fe = FeCl2 + H2
FeCl2 + 2AgNO3 = 2AgCl + Fe(NO3)2
2AgCl = 2Ag + Cl2
2Cl2 + 2H2O —> 4HCl + O2
Cl + 2Na —-> 2NaCl (nhiệt độ)
NaCl + AgNO3 —> AgCl + NaNO3
Bạn ở dưới sai sai thì phải:
2Na + Cl2 -> (t°) 2NaCl
NaCl + AgNO3 -> AgCl + AnNO3