Tìm x: 3x.4.0,05+5x.2.0,05+7x.0,05=11,6 (Trình bày đầy đủ các bước giải)
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tối khoảng 9h bạn đăng chắc chắn có nhiều người giỏi giải nha
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\(A=27x^3+108x^2+144x+64\)
\(=\left(3x\right)^3+3.\left(3x\right)^2.4+3.3x.4^2+4^3\)
\(=\left(3x+4\right)^3=\left(3.32+4\right)^3=100^3=1000000\)
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b: \(\Leftrightarrow n+1\in\left\{1;-1;2;-2;4;-4\right\}\)
hay \(n\in\left\{0;-2;1;-3;3;-5\right\}\)
c: \(\Leftrightarrow n+2\in\left\{1;-1;5;-5\right\}\)
hay \(n\in\left\{-1;-3;3;-7\right\}\)
d: \(\Leftrightarrow n+2\in\left\{1;-1;2;-2;4;-4\right\}\)
hay \(n\in\left\{-1;-3;0;-4;2;-6\right\}\)
a: \(\Leftrightarrow n-1\in\left\{1;-1;5;-5\right\}\)
hay \(n\in\left\{2;0;6;-4\right\}\)
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\(9x^2-x+\dfrac{1}{36}\)
\(=\left(3x\right)^2-2\cdot3x\cdot\dfrac{1}{6}+\left(\dfrac{1}{6}\right)^2\)
\(=\left(3x-\dfrac{1}{6}\right)^2\)
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a: \(5x-20y=5\left(x-4y\right)\)
b: \(x^2+x^2y+x^2y^2=x^2\left(1+y+y^2\right)\)
c: \(x\left(x+y\right)-\left(5x+5y\right)=\left(x+y\right)\left(x-5\right)\)
d: \(5\left(x-y\right)+y\left(x-y\right)=\left(x-y\right)\left(y+5\right)\)
=>0,6x+0,5x+0,35x=11,6
=>1,45x=11,6
hay x=8