(0,125)^3*2^9
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
\(\left(-0,125\right)\times7,9\times80\)
\(=\left(-0,9875\right)\times80\)
\(=79.\)
\(\left(0,125\right)\times1\times0,25\times8\times\left(-4\right)\)
\(=0,125\times0,25\times8\times\left(-4\right)\)
\(=0,03125\times8\times\left(-4\right)\)
\(=0,25\times\left(-4\right)\)
\(=\left(-1\right).\)
Bài 2:
\(x+\frac{8}{3}^2=\frac{1}{9}\)
\(x+16=\frac{1}{9}\)
\(x=\frac{1}{9}-16.MSC=9\)
\(x=\frac{1}{9}-\frac{144}{9}\)
\(x=\frac{-143}{9}.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\left(\dfrac{7}{2}-2x\right).\dfrac{10}{3}=\dfrac{22}{3}\Leftrightarrow\dfrac{7}{2}-2x=\dfrac{22}{10}=\dfrac{11}{5}\)
\(\Leftrightarrow2x=\dfrac{13}{10}\Leftrightarrow x=\dfrac{13}{20}\)
b, \(\dfrac{4x}{9}=\dfrac{9}{8}-\dfrac{125}{1000}=1\Leftrightarrow x=\dfrac{9}{4}\)
c, \(-\dfrac{x}{21}=\dfrac{60}{21}\Rightarrow x=-60\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(\frac{3}{4}\cdot x=1\)
\(x=1:\frac{3}{4}=\frac{4}{3}\)
b) \(2\frac{4}{7}\cdot x=\frac{9}{8}-0,125\)
\(\frac{18}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)
\(\frac{18}{7}\cdot x=1\)
\(x=1:\frac{18}{7}=\frac{7}{18}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
9/8 + 3/8x = 0,125 = 1/8
3/8x = 1/8 - 9/8 = -1
=> x = -1 : 3/8 = -8/3
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
\(\begin{array}{l}\frac{{ - 3}}{{10}} - 0,125 + \frac{{ - 7}}{{10}} + 1,125 \\= \left( {\frac{{ - 3}}{{10}} + \frac{{ - 7}}{{10}}} \right) + \left( {1,125 - 0,125} \right)\\ = - 1 + 1 \\= 0\end{array}\)
b)
\(\begin{array}{l}\frac{{ - 8}}{3}.\frac{2}{{11}} - \frac{8}{3}:\frac{{11}}{9} \\= \frac{8}{3}.\frac{{ - 2}}{{11}} - \frac{8}{3}.\frac{9}{{11}}\\ = \frac{8}{3}.\left( {\frac{{ - 2}}{{11}} - \frac{9}{{11}}} \right)\\ =\frac{{ - 8}}{3}.\frac{-11}{11}\\= \frac{8}{3}.\left( { - 1} \right) \\= \frac{{ - 8}}{3}\end{array}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
\(\begin{array}{l}x.\frac{{14}}{{27}} = \frac{{ - 7}}{9}\\x = \frac{{ - 7}}{9}:\frac{{14}}{{27}}\\x = \frac{{ - 7}}{9}.\frac{{27}}{{14}}\\x = \frac{{ - 3}}{2}\end{array}\)
Vậy \(x = \frac{{ - 3}}{2}\).
b)
\(\begin{array}{l}\left( {\frac{{ - 5}}{9}} \right):x = \frac{2}{3}\\x = \left( {\frac{{ - 5}}{9}} \right):\frac{2}{3}\\x = \left( {\frac{{ - 5}}{9}} \right).\frac{3}{2}\\x = \frac{{ - 5}}{6}\end{array}\)
Vậy \(x = \frac{{ - 5}}{6}\).
c)
\(\begin{array}{l}\frac{2}{5}:x = \frac{1}{{16}}:0,125\\\frac{2}{5}:x = \frac{1}{{16}}:\frac{1}{8}\\\frac{2}{5}:x = \frac{1}{{16}}.8\\\frac{2}{5}:x = \frac{1}{2}\\x = \frac{2}{5}:\frac{1}{2}\\x = \frac{2}{5}.2\\x = \frac{4}{5}\end{array}\)
Vậy \(x = \frac{4}{5}\)
d)
\(\begin{array}{l} - \frac{5}{{12}}x = \frac{2}{3} - \frac{1}{2}\\ - \frac{5}{{12}}x = \frac{4}{6} - \frac{3}{6}\\ - \frac{5}{{12}}x = \frac{1}{6}\\x = \frac{1}{6}:\left( { - \frac{5}{{12}}} \right)\\x = \frac{1}{6}.\frac{{ - 12}}{5}\\x = \frac{{ - 2}}{5}\end{array}\)
Vậy \(x = \frac{{ - 2}}{5}\).
Chú ý: Khi trình bày lời giải bài tìm x, sau khi tính xong, ta phải kết luận.
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (1,4 + 5,8) ; 3
= 7,2 : 3 = 2,4
b) (1,25 x 4 x 0,9) ; ( 9 x 5)
=(5 x 0,9) ; (9x 5 )
= 4,5 : 45
= 0,1
c) 2019 x 2 + 2019 x 8
= 2019 x ( 2 + 8)
= 2019 x 10
=20190
#chanh
a. 1,4 : 3 + 5,8 : 3
= (1,4 + 5,8) : 3
= 7,2 : 3
= 2,4
b. (1,25 x 3,6) : (9 x 5)
= 4,5 : 45
= 0,1
c. 2019 x 2 + 2019 : 0,125
= 2019 x 2 + 2019 x 8
= 2019 x (2 + 8)
= 2019 x 10 = 20190
![](https://rs.olm.vn/images/avt/0.png?1311)
35×11×9×0,125×2011×(3÷4-0,75)
=35×11×9×0,125×2011×(0,75 - 0,75 )
= 35×11×9×0,125×2011x 0
=> = 0
\(\left(0,125\right)^3.2^9=\dfrac{1}{512}.512=1\)