Tìm x biết x ⋮ 3 , 324 ⩽ x ⩽ 334
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tc tỉ lệ thức,ta có (ra số hơi to thông cảm )
\(\Leftrightarrow\frac{22990993x+80556557}{1870865100}=-\frac{4}{1}\Rightarrow\left(22990993x+80556557\right)1=-1870865100.4\)
\(\frac{\left(22990993x+80556557\right)1}{22990933x}=-\frac{1870865100.4}{22990993x}\)( chia 2 vế cho 2290933x)
\(\Rightarrow\frac{22990933x+80556557}{22990933x}=-\frac{1870865100.4}{22990933x}\)
=>x=-329
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Từ 1 đến x có (x-1):2+1 số hạng
Số cặp là ((x-1):2+1):2
tổng mỗi cặp là 1+x
Suy ra x=79
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\(3^x+3^x.3=324\)
\(3^x.\left(1+3\right)=324\)
\(3^x.4=324\)
\(3^x=324:4\)
\(3^x=81\)
\(3^x=3^4\)
\(\Rightarrow x=4\)
3x + 3x+1 = 324
3x .1+ 3x.3 = 324
3x.(1+3) = 324
3x .4 = 324
3x = 324:4
3x = 81
81=3 .3.3.3 =34 => 81 =34=> x =4
Vậy x=4
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\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}=-4\)
<=>\(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)=0\)
<=>\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}=0\)
<=>\(\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\right)=0\)
Vì \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\ne0\Rightarrow x+329=0\Leftrightarrow x=-329\)
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a) X + 5 9 = 3 2 ⇒ X = 3 2 - 5 9 = 27 18 - 10 18 = 17 18 .
b) X + 1 1 2 = 3 3 4 ⇒ X = 3 3 4 - 1 1 2 = 15 4 - 3 2 = 9 4 .
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a ) x : 4 5 + 5 2 = − 3 3 4 ⇒ x : 4 5 = − 3 3 4 − 5 2 ⇒ x : 4 5 = − 11 2 ⇒ x = − 22 5 .
b ) x − 3 4 = 1 5 4 ⇒ x − 3 4 = 9 4 ⇒ x = 3 x − 3 4 = − 9 4 ⇒ x = − 3 2 .