Tính \(\frac{21}{3.10}+\frac{15}{10.15}+\frac{27}{15.24}+\frac{9}{24.2}+\frac{33}{27.38}\)
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29-x/21 + 27-x/23 + 25-x/25 + 23-x/27 + 21-x/29 = -5
1 + 29-x/21 + 1 + 27-x/23 + 1 + 25-x/25 + 1 + 23-x/27 + 1 + 21-x/29 = 0
50-x/21 + 50-x/23 + 50-x/25 + 50-x/27 + 50-x/29 = 0
(50-x) (1/21 + 1/23 + 1/25 + 1/27 + 1/29) = 0
Vì: 1/21 + 1/23 + 1/25 + 1/27 + 1/2 > 0
=> 50 - x = 0
x = 50
Vậy x = 50
\(\frac{-1}{3}+\frac{0,2-0,3+\frac{5}{11}}{-0,3+\frac{9}{16}-\frac{15}{12}}\)
\(=\frac{-1}{3}+\frac{\frac{2}{10}-\frac{3}{10}+\frac{5}{11}}{\frac{-3}{10}+\frac{9}{16}-\frac{15}{12}}\)
\(=\frac{-1}{3}+\frac{\frac{39}{110}}{\frac{-79}{80}}\)
\(=\frac{-1}{3}-\frac{312}{869}\)
\(=\frac{-1805}{2607}\)

Bài 1:
A = \(\frac15\) + \(\frac{3}{17}\) - \(\frac43\) + (\(\frac45\) - \(\frac{3}{17}\) + \(\frac13\)) - \(\frac17\) + (- \(\frac{14}{30}\))
A = \(\frac15\) + \(\frac{3}{17}\) - \(\frac43\) + \(\frac45\) - \(\frac{3}{17}\) + \(\frac13\) - \(\frac17\) - \(\frac{14}{30}\)
A = (\(\frac15\) + \(\frac45\)) + (\(\frac{3}{17}\) - \(\frac{3}{17}\)) - (\(\frac43-\frac13\)) - \(\frac{30}{210}\) - \(\frac{98}{210}\)
A = 1 + 0 - 1 - (\(\frac{30}{210}+\frac{98}{210}\))
A = 1 - 1 - \(\frac{228}{210}\)
A = 0 - \(\frac{128}{210}\)
A = - \(\frac{64}{105}\)
Bài 2:
B= (\(\frac58\) - \(\frac{4}{12}\) + \(\frac32\)) - (\(\frac58\) + \(\frac{9}{13}\)) - (\(\frac{-3}{2}\)) + \(\frac{7}{-15}\)
B = \(\frac58\) - \(\frac{4}{12}\) + \(\frac32\) - \(\frac58\) - \(\frac{9}{13}\) + \(\frac32\) - \(\frac{7}{15}\)
B = (\(\frac58\) - \(\frac58\)) + (\(\frac32\) + \(\frac32\)) - (\(\frac13\) + \(\frac{9}{13}\) + \(\frac{7}{15}\))
B = 0 + 3 - (\(\frac{65}{195}\) + \(\frac{135}{195}\) + \(\frac{91}{195}\))
B = 3 - (\(\frac{200}{195}\) + \(\frac{91}{195}\))
B = 3 - \(\frac{97}{65}\)
B = \(\frac{195}{65}\) - \(\frac{97}{65}\)
B = \(\frac{98}{65}\)

21/54 + 3/75 : (39/65) + 29/200 - ( 33/600 ) : 21/9 / 7^2 - 73/4 + 41/12 - 97/6
= 21/54 + 3/75 : (39/65) + 29/200 - 33/600 . 9/21 / 49 - 73/4 + 41/12 - 97/6
= 21/54 + 3/75 : 149/200 - 33/1400 / 49 - 73/4 + ( -51/4 )
= 21/54 + 3/75 : 101/140 / 123/4 + ( -51/4 )
= 21/54 + 3/75 : 101/140 / 18
= 21/54 + 3/75 : 101/140 . 1/18
= 21/54 + 3/75 : 101/2520
= 21/54 + 3/75 . 2520/101
= 21/54 + 504/505
Tim hai so tu nhiên a,b toa man dieu kien a+2b=48 va (a,b)+3=144

\(a,\frac{26}{60}+\frac{3}{15}=\frac{13}{30}+\frac{1}{5}=\frac{13}{30}+\frac{6}{30}=\frac{19}{30}\)
\(b,\frac{4}{26}+\frac{33}{78}=\frac{2}{13}+\frac{11}{26}=\frac{4}{26}+\frac{11}{26}=\frac{15}{26}\)
\(c,\frac{25}{40}-\frac{3}{12}=\frac{5}{8}-\frac{1}{4}=\frac{5}{8}-\frac{2}{8}=\frac{3}{8}\)
\(d,\frac{21}{27}+\frac{10}{54}+\frac{5}{15}=\frac{7}{9}+\frac{5}{27}+\frac{1}{3}=\frac{21}{27}+\frac{5}{27}+\frac{9}{27}=\frac{35}{27}\)
~Study well~
#Thạc_Trân