A= 212.35-46.92 / (22.3)6+84.35 - 510.73-255.492 / (125.7)3.59.143
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VT
3
20 tháng 9 2017
a) 34.18+23.18+43.18
18. (34+23+43)
18.100=1800
b)54.(112+88)+(92+118).46
54.200+210.46
10800+9660=20460
NP
0
G
22 tháng 3 2022
\(A=\dfrac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
\(=\dfrac{5.2^{18}.3^{18}.2^{12}-2.2^{28}.3^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
\(=\dfrac{5.2^{20}.3^{18}-2^{29}.3^{18}}{2^{28}.3^{18}\left(5-7.2\right)}\)
\(=\dfrac{2^{29}.3^{18}\left(5.2-1\right)}{2^{28}.3^{18}\left(5-14\right)}=\dfrac{2.9}{-9}=-2\)
5 tháng 2 2023
`a) ((-14).15)/(21.(-10))`
`=(-7.3.5.3)/(7.3.(-2).5)`
`=3/2`
`b) ((-7).12)/((-16).(-14))`
`=(-7.3.2.2)/(-2.2.2.(-7).2)`
`=(-3)/4`
`c) ((-11).(-5))/(15.22) `
`=(-11.(-5))/(3.5.11.2)`
`=1/6`
`d) ((-10).(-18))/((-6).25.7)`
`=(-5.2.-2.3.3)/(-2.3.5.5.7)`
`=6/35`
`e) (5.7-7.9)/(7.2+6.7)`
`=(7.(5-9))/(7.(2+6))`
`=-4/8`
`=-1/2`
`f) (11.9-22.3)/(33.2)`
`=(33.(3-2))/(33.2)`
`=1/2`
20 tháng 8
Ta có: \(\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6}\)
\(=\frac{2^{12}\cdot3^5-2^{12}\cdot3^4}{2^{12}\cdot3^6}=\frac{2^{12}\cdot3^4\left(3-1\right)}{2^{12}\cdot3^6}\)
\(=\frac{3^4\cdot2}{3^6}=\frac{2}{3^2}=\frac29\)
Ta có: \(\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
\(=\frac{5^{10}\cdot7^3-5^{10}\cdot7^4}{5^9\cdot7^3+5^9\cdot7^3\cdot2^3}\)
\(=\frac{5^{10}\cdot7^3\left(1-7\right)}{5^9\cdot7^3\left(1+2^3\right)}=5\cdot\frac{-6}{9}=5\cdot\frac{-2}{3}=-\frac{10}{3}\)
Ta có: \(A=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
\(=\frac29+\frac{10}{3}=\frac29+\frac{30}{9}=\frac{32}{9}\)
22 tháng 10 2021
\(\hept{\begin{cases}\\\end{cases}\hept{\begin{cases}\\\\\end{cases}}\orbr{\begin{cases}\\\end{cases}}^{ }^2_{ }\widebat{ }\varnothing\alpha}\)ok
chua
VT
0
25 tháng 5 2022
\(A=\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
\(=\dfrac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}-\dfrac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3+5^9.2^3.7^3}\)
\(=\dfrac{2^{12}.3^4.\left(3-1\right)}{2^{12}.3^5.\left(3+1\right)}-\dfrac{5^{10}.7^3.\left(1-7\right)}{5^9.7^3.\left(1+2^3\right)}\)
\(=\dfrac{2^{12}.3^4.2}{2^{12}.3^5.4}-\dfrac{5^{10}.7^3.\left(-6\right)}{5^9.7^3.9}\)
\(=\dfrac{1}{6}-\dfrac{-10}{3}\)
\(=\dfrac{7}{2}\)