a) 505*2*35 b) 20*178*4
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a) 31 . { 330 : [178 – 4 . ( 35 – 21 : 3 )]} = 31 . { 330 : [178 – 4 . ( 35 – 7)]}
= 31 . { 330 : [178 – 4 . 28]} = 31 . { 330 : [178 – 112]}
= 31 . { 330 : 66 } = 31 . 5 = 155
b) ( 5 19 . 5 14 ) : 5 32 = 5 33 : 5 32 = 5
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\(1,A=\dfrac{2}{3\cdot7}+\dfrac{2}{7\cdot11}+\dfrac{2}{11\cdot15}+...+\dfrac{2}{99\cdot103}\\ 2A=\dfrac{4}{3\cdot7}+\dfrac{4}{7\cdot11}+\dfrac{4}{11\cdot15}+...+\dfrac{4}{99\cdot103}\\ 2A=\dfrac{1}{3}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{11}+...+\dfrac{1}{99}-\dfrac{1}{103}\\ 2A=\dfrac{1}{3}-\dfrac{1}{103}=\dfrac{100}{309}\\ A=\dfrac{100}{309}\cdot\dfrac{1}{2}=\dfrac{50}{309}\)
\(2,A=\dfrac{7}{2}+\dfrac{7}{6}+\dfrac{7}{12}+\dfrac{7}{20}+\dfrac{7}{30}+\dfrac{7}{42}+\dfrac{7}{56}+\dfrac{7}{72}+\dfrac{7}{90}\\ A=7\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{9\cdot10}\right)\\ A=7\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\\ A=7\left(1-\dfrac{1}{10}\right)=7\cdot\dfrac{9}{10}=\dfrac{63}{10}\)
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2 x 175 x 5
= ( 2 x 5 ) x 175
= 10 x 175
= 1750
263 x 15 x 4
= 263 x ( 15 x 4 )
= 263 x 60
15780
20 x 198 x 4
= ( 20 x 4 ) x 198
= 80 x 198
= 15840
505 x 35 x 2
= 505 x ( 35 x 2 )
= 505 x 70
= 35350
tk nha
2 x 175 x 5
= ( 2 x 5 ) x 175
= 10 x 175
= 1750
20 x 198 x 4
= ( 20 x 4 ) x 198
= 80 x 198
= 15840
còn lại tự làm nha
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Phương pháp giải:
a) Phân tích số có ba chữ số thành tổng các trăm, chục, đơn vị.
b) Viết số có ba chữ số từ tổng trăm, chục, đơn vị đã cho.
Lời giải chi tiết:
a) Mẫu : 482 = 400 + 80 + 2
687 = 600 + 80 + 7
141 = 100 + 40 + 1
735 = 700 + 30 + 5
460 = 400 + 60
505 = 500 + 5
986 = 900 + 80 + 6
b) Mẫu : 200 + 50 + 9 = 259
600 + 70 + 2 = 672
300 + 90 + 9 = 399
400 + 40 + 4 = 444
900 + 50 + 1 = 951
500 + 20 = 520
700 + 3 = 703
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a) 31 . { 330 : [178 – 4 . ( 35 – 21 : 3 )]} = 31 . { 330 : [178 – 4 . ( 35 – 7)]}
= 31 . { 330 : [178 – 4 . 28]} = 31 . { 330 : [178 – 112]}
= 31 . { 330 : 66 } = 31 . 5 = 155
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\(3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot\left(7^8-7^6+7^0\right)\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot5647153\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-45177224\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300--45176678\right\}\)
\(=3^3\cdot5^3-20\cdot45176978\)
\(=3375-903539560\)
\(=-903536185\)
\(626500:\left\{50^2:\left[178-4\cdot\left(35-21:3\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot\left(35-7\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot28\right]\right\}\)
\(=626500:\left\{50^2:\left[178-112\right]\right\}\)
\(=626500:\left\{50^2:66\right\}\)
\(=626500:\frac{1250}{33}\)
\(=\frac{82698}{5}\)
CHUC BAN HOC TOT >.<