1 + -1/60 + 19/20 < x/36 < 58/90 + 59/72< -1/60 . Tìm x
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NH
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NP
0
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LL
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DQ
0
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PH
2
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7 tháng 6 2020
\(1+\frac{-1}{60}+\frac{19}{120}< \frac{x}{36}< \frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
=> \(\frac{137}{120}< \frac{x}{36}< \frac{521}{360}\)
=> \(\frac{411}{360}< \frac{10x}{360}< \frac{521}{360}\)
=> 411 < 10x < 521
=> x \(\in\){ 42,43,44,...,52}
DQ
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