tìm x biết : 2X+2 - 2x =96
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Xét cấp số cộng 1, 6, 11, ..., 96.
Ta có: 96 = 1 + 5(n − 1) ⇒ n = 20
Suy ra
Và 2x.20 + 970 = 1010
Từ đó x = 1
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Ta có :
a)|2x-2|-3x+1=-2
|2x-2|-3x=-3
|2x-2|=3x-3
Để biểu thức trên có nghĩa thì 3x-3>0 hoặc=0.Khi đó x>1 hoặc =1
TH1:2x-2=3x-3
2x-3x=-3+2
x=1 (Thỏa mãn)
TH2:2x-2=-(3x-3)
2x-2=-3x+3
2x+3x=3+2
5x=5
x=1(Thỏa mãn)
Vậy x=1
b)x-96=(443-x)-15
x-96=443-x-15
x+x=443-15+96
2x=524
x=262
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2x - 4(5 - x) = 2x + 16
=> 4(5 - x) = 2x - (2x + 16)
=> 4(5 - x) = 2x - 2x - 16
=> 4(5 - x) = -16
=> 5 - x = -4
=> x = 9
Vậy...
Bài 2: Tìm số tự nhiên x biết:
a) 12(x−1)∶3=43+23 c) (7x−11)3=23.52+200
b) 128−3(x+4)=23 d) 2x+2−2x=96
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a: =>12x-64=32
=>12x=96
=>x=8
b: =>x-1=5
=>x=6
c: =>2^x*3=96
=>2^x=32
=>x=5
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a) \(2^x\cdot2^2-2^x=96\)
\(2^x\cdot\left(4-1\right)=96\)
\(2^x=32=2^5\)
=> x = 5
b) \(\left(2x+1\right)^3=7^3\)
=> 2x +1 = 7
=> 2x = 6
=> x = 3
Vậy,..........
a. 2x+2 - 2x = 96
2x . 22 - 2x = 96
2x. (22 - 1) = 96
2x = 96 : 3
2x = 32
2x = 25
x = 5
b. (2x + 1)3 = 343
(2x + 1)3 = 73
2x + 1 = 7
2x = 7 - 1
x = 6 : 2
x = 3
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\(1,\Leftrightarrow x^2+10x+25=x^2-4x-21\\ \Leftrightarrow14x=-46\\ \Leftrightarrow x=-\dfrac{23}{7}\\ 2,\Leftrightarrow x^3+8=15+x^3+2x\\ \Leftrightarrow2x=-7\Leftrightarrow x=-\dfrac{7}{2}\\ 3,\Leftrightarrow\left(x+3\right)^2=0\\ \Leftrightarrow x=-3\\ 4,\Leftrightarrow x^3-9x^2+27x-27=0\\ \Leftrightarrow\left(x-3\right)^3=0\\ \Leftrightarrow x-3=0\Leftrightarrow x=3\\ 5,\Leftrightarrow4x^2+4x+1-4x^2-16x-16=9\\ \Leftrightarrow-12x=24\Leftrightarrow x=-2\\ 6,\Leftrightarrow x^2-3x+5x-15=0\\ \Leftrightarrow\left(x-3\right)\left(x+5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
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2x + 2x + 1 = 96
2x + 2x . 2 = 96
2x . (1 + 2) = 96
2x . 3 = 96
2x = 96 : 3
2x = 32
2x = 25
x = 5
2^x*2^2-2^X=96
2^x(4-1)=96
2^x*3=96
2^x=96/3
2^x=32
2^x=2^5
Vậy x=5