Tìm x:x*8*6=96
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x:8=35( dư 4)
x= (35x8)+4
x=.....
Các bài khác tương tự.
Số dư trong bài x:8= 35( số dư nhỏ nhất bằng 7)
dễ mà mk làm 1 câu mẫu cho bn nhé còn các câu sau tương tự
x : 8 = 35 ( du 4 )
x = 35 * 8 + 4
x = 284
k mk nha
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\(x-\dfrac{4}{12}=-\dfrac{5}{6}\)
⇔\(x-\dfrac{1}{3}=-\dfrac{5}{6}\)
⇔\(x=-\dfrac{1}{2}\)
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\(\frac{x+1}{2}=\frac{8}{x+1}\Rightarrow\left(x+1\right)^2=8.2\)
=>(x+1)2=16
=>x+1=\(\sqrt{16}\)
=>x+1=4
=>x=3
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\(\dfrac{x}{5}=\dfrac{5}{6}-\dfrac{19}{30}\)
\(\Leftrightarrow\dfrac{x}{5}=\dfrac{25}{30}-\dfrac{19}{30}=\dfrac{6}{30}=\dfrac{1}{5}\)
\(\Leftrightarrow x=1\)
Ta có : \(\dfrac{x}{5}=\dfrac{5}{6}+\left(-\dfrac{19}{30}\right)=\dfrac{25}{30}-\dfrac{19}{30}=\dfrac{1}{5}\)
\(\Leftrightarrow5x=5\)
\(\Leftrightarrow x=1\)
Vậy ...
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\(\Leftrightarrow x+\dfrac{1}{8}=\dfrac{1}{6}\\ \Leftrightarrow x=\dfrac{1}{24}\)
\(\Rightarrow x+\dfrac{1}{8}=\dfrac{1}{6}\\ \Rightarrow x=\dfrac{1}{24}\)
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\(\Leftrightarrow\left(x+2\right)^2\cdot\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=-1\end{matrix}\right.\)
Ta có x*6*8=96
=>x*48=96
=>x =96:48
=>x =2