Giải giúp mik vs ak
K
Khách
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20 tháng 9 2021
1) \(=\left(2x\right)^2-3^2=\left(2x-3\right)\left(2x+3\right)\)
2) \(=8^2-\left(5y\right)^2=\left(8-5y\right)\left(8+5y\right)\)
3) \(=1-\left(7x\right)^2=\left(1-7x\right)\left(1+7x\right)\)
4) \(=\left(16xy\right)^2-1=\left(16xy-1\right)\left(16xy+1\right)\)
5) \(=2\left(x^2-9y^2\right)=2\left(x-3y\right)\left(x+3y\right)\)
6) \(=3\left(a^2-4b^4\right)=3\left(a-2b^2\right)\left(a+2b^2\right)\)
7) \(=\left(a^2\right)^2-4^2=\left(a^2-4\right)\left(a^2+4\right)=\left(a-2\right)\left(a+2\right)\left(a^2+4\right)\)
8) \(=9^2-\left(x^2\right)^2=\left(9-x^2\right)\left(9+x^2\right)=\left(3-x\right)\left(3+x\right)\left(9+x^2\right)\)
9) \(=\left(6b\right)^2-a^2=\left(6b-a\right)\left(6b+a\right)\)
10) \(=\left(8x^3\right)^2-27^2=\left(8x^3-27\right)\left(8x^3+27\right)=\left(2x-3\right)\left(4x^2+6x+9\right)\left(2x+3\right)\left(4x^2-6x+9\right)\)
TT
2
DV
2
6 tháng 7 2023
C = 6/2.5 + 6/5.8 + 6/8.11 +...+ 6/29.32
C = 2.(3/2.5 + 3/5.8 + 3/8.11 + ... + 3/29.32)
C = 2.(1/2 - 1/5 + 1/5 - 1/8 + 1/8 - 1/11 + ... + 1/29 - 1/32)
C = 2.(1/2 - 1/32)
C = 2.15/32
C = 15/16
KT
1
S
subjects
CTVHS
14 tháng 8
bài 1:
\(1)x+\frac34=\frac43\Rightarrow x=\frac43-\frac34=\frac{7}{12}\)
\(2)x-\frac35=\frac{4}{15}\Rightarrow x=\frac{4}{15}+\frac35=\frac{13}{15}\)
\(3)-x-\frac{2}{15}=\frac{7}{10}\Rightarrow x=-\frac{2}{15}-\frac{7}{10}=-\frac56\)
\(4)\frac79-x=\frac{1}{12}\Rightarrow x=\frac79-\frac{1}{12}=\frac{25}{36}\)
\(5)\frac34x=\frac{-5}{6}\Rightarrow x=-\frac56:\frac34=-\frac56\cdot\frac43=-\frac{10}{9}\)
\(6)\left(x+\frac23\right)\cdot\frac45=-\frac{8}{15}\Rightarrow x+\frac23=-\frac{8}{15}:\frac45\)
\(x+\frac23=-\frac{8}{15}\cdot\frac54=-\frac23\)
\(x=-\frac23-\frac23=-\frac43\)
\(7)\frac67:x=-\frac{8}{21}\Rightarrow x=\frac67:\left(-\frac{8}{21}\right)\)
\(x=\frac67\cdot\left(-\frac{21}{8}\right)=-\frac94\)
\(8)x:\frac35=-\frac52\Rightarrow x=-\frac52\cdot\frac35=-\frac32\)
\(9)\frac34:\left(\frac14+x\right)=-\frac56\Rightarrow\frac14+x=\frac34:\left(-\frac56\right)\)
\(\frac14+x=\frac34\cdot\left(-\frac65\right)=-\frac{9}{10}\)
\(\Rightarrow x=-\frac{9}{10}-\frac14=-\frac{23}{20}\)
bài 2:
\(1)\frac34+\frac14x=-\frac56\Rightarrow\frac14x=-\frac56-\frac34\)
\(\frac14x=-\frac{19}{12}\Rightarrow x=-\frac{19}{12}:\frac14\)
\(x=-\frac{19}{12}\cdot4=-\frac{19}{3}\)
\(2)3\frac12-\frac12x=-\frac23\Rightarrow\frac72-\frac12x=-\frac23\)
\(\frac12x=\frac72-\left(-\frac23\right)=\frac{25}{6}\)
\(x=\frac{25}{6}:\frac12=\frac{25}{6}\cdot2=\frac{25}{3}\)
\(3)x:\frac12+\frac32=\frac54\Rightarrow x\cdot2=\frac54-\frac32\)
\(x\cdot2=-\frac14\Rightarrow x=-\frac14:2=-\frac14\cdot\frac12=-\frac18\)
\(4)\frac58-\frac38:x=\frac12\Rightarrow\frac38\cdot\frac{1}{x}=\frac58-\frac12\)
\(\frac{3}{8x}=\frac18\Rightarrow24=8x\Rightarrow x=3\)
\(5)\frac32x-\frac14=\frac47\Rightarrow\frac32x=\frac47+\frac14\)
\(\frac32x=\frac{23}{28}\Rightarrow x=\frac{23}{28}:\frac32=\frac{23}{28}\cdot\frac23=\frac{23}{42}\)
\(6)\frac13+\frac12:x=\frac15\Rightarrow\frac12\cdot\frac{1}{x}=\frac15-\frac13\)
\(\frac{1}{2x}=-\frac{2}{15}\Longrightarrow4x=-15\Rightarrow x=-\frac{15}{4}\)
MN
2
24 tháng 12 2022
1 Lan goes to the supermarket on foot
2 Our garden has many flowers
3 He has black hair
4 We don't have to finish the task today (not necessary => don't have to: không cần làm gì, còn must not là không được làm gì nên câu này đề cho must là sai)
5 Are there 23 students in your class?
6 Lan is not as young as Minh
14 tháng 12 2019
10 + 20 + 10 + 90
= ( 10 + 20 ) + ( 10 + 90 )
= 30 + 100
= 130
HỌC TỐT
29 tháng 12 2019
10 + 20 + 10 + 90
= ( 10 + 20 ) + ( 10 + 90 )
= 30 + 100
= 130