phân tích đa thức thành nhân tử 5y^3-10xy^2+5yx^2-20y
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do hơi bận nên mk ghi đáp án nha, ko hiểu đâu ib mk
a) \(3xy^2-2xy+12x=x\left(3y^2-2y+12\right)\)
b) \(x^3-10x^2+25x-16xy^2=x\left(x-4y-5\right)\left(x+4y-5\right)\)
c) \(5y^3-10xy^2+5x^2y-20y=5y\left(y-x-2\right)\left(y-x+2\right)\)
d) \(x^2+2xy+y^2-xz-yz=\left(x+y\right)\left(x+y-z\right)\)
e) \(9x^2+y^2+6xy=\left(3x+y\right)^2\)
f) \(8-12x+6x^2-x^3=\left(2-x\right)^3\)
g) \(125x^3-75x^2+15x-1=\left(5x-1\right)^3\)
h) \(x^2-xz-9y^2+3yz=\left(x-3y\right)\left(x+3y-z\right)\)
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5x2-10xy+5y2-20z2
=5(x2-2xy+y2-4z2)
=5[(x-y)2-4z2]
=5(x-y-2z)(x-y+2z)
dễ hiểu thôi.hơi vắn tắt
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5x^2+10xy+5y^2
=5.(x2+2xy+y2)
=5.(x+y)2
x^3-6x^2+9x
=x.(x2-6x+9)
=x.(x-3)2
xy+y^2-x-y
=y.(x+y)-(x+y)
=(x+y)(y-1)
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Câu 1 đề sai rồi bạn ơi
Câu 2/ 5(x2 + 2xy + y2 ) = 5(x +y )2
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5x2 - 10xy + 5y2 - 20z2
=5(x2 - 2xy + y2 - 4z2)
= 5[ (x2 - 2xy + y2) - (2z)2]
= 5[(x-y)2 - (2z)2]
= 5(x-y-2z)(x-y+2z)
5x2-10xy+5y2-20z2
=5(x2-2xy+y2-4z2)
=5[(x-y)2-(2z)2]
=5(x-y-2z)(x-y+2z)
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\(5x^2-10xy^2+5y^4\)
\(=5.\left(x^2-2xy^2+y^4\right)\)
\(=5.\left[x^2-2xy^2+\left(y^2\right)^2\right]\)
\(=5.\left(x-y^2\right)^2\)
\(5y^3-10xy^2+5yx^2-20y=5y\left(y^2-2xy+x^2-4\right)\)
\(=5y\left[\left(x+y\right)^2-4\right]\)
\(=5y\left(x+y-2\right)\left(x+y+2\right)\)
Chúc bạn học tốt.