tìm x:
4,5 - 2x . 147 =\(\dfrac{11}{14}\)
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d: =>-x-5/6=7/12-4/12=3/12=1/4
=>-x=1/4+5/6=13/12
hay x=-13/12
e: =>x+3=-5
hay x=-8
f: =>4,5-2x=-1/2
=>2x=5
hay x=5/2
a, 4,5 - 2x . 147 = 1114
2x . 147 = 4,5 - 1114
2x . 147 = -1109,5
2x = -1109,5 / 147
2x = \(-\dfrac{317}{42}\)
x = \(-\dfrac{317}{42}:2\)
x = \(-\dfrac{317}{84}\)
b, ( x + 14 - 13 ) : ( 2 + 16 - 14 ) = 746
( x + 1 ) : 4 = 746
x + 1 = 746 . 4
x + 1 = 2984
x = 2984 - 1
x = 2983
c, \(\dfrac{13}{15}-\left(\dfrac{13}{21}+x\right).\dfrac{7}{12}=\dfrac{7}{10}\)
\(\left(\dfrac{13}{21}+x\right).\dfrac{7}{12}=\dfrac{13}{15}-\dfrac{7}{10}\)
\(\left(\dfrac{13}{21}+x\right).\dfrac{7}{12}=\dfrac{1}{6}\)
\(\dfrac{13}{21}+x=\dfrac{1}{6}:\dfrac{7}{12}\)
\(\dfrac{13}{21}+x=\dfrac{2}{7}\)
\(x=\dfrac{2}{7}-\dfrac{13}{21}\)
\(x=-\dfrac{1}{3}\)
\(\left(4,5-2x\right)\cdot1\dfrac{4}{7}=\dfrac{11}{14}\)
\(\left(\dfrac{9}{2}-2x\right)\cdot\dfrac{11}{7}=\dfrac{11}{14}\)
\(\dfrac{9}{2}-2x=\dfrac{11}{14}:\dfrac{11}{7}\)
\(\dfrac{9}{2}-2x=\dfrac{1}{2}\)
\(2x=\dfrac{9}{2}-\dfrac{1}{2}\)
\(2x=\dfrac{8}{2}\)
\(x=\dfrac{8}{2}:2\)
`x=2`
(4,5 - 2\(x\)) (-1\(\dfrac{4}{7}\)) = \(\dfrac{11}{14}\)
(4,5 - 2\(x\)) (-\(\dfrac{11}{7}\)) = \(\dfrac{11}{14}\)
4,5 - 2\(x\) = \(\dfrac{11}{14}\) : ( - \(\dfrac{11}{7}\))
4,5 - 2\(x\) = \(\dfrac{11}{14}\) \(\times\) (- \(\dfrac{7}{11}\))
4,5 - 2\(x\) = - \(\dfrac{1}{2}\)
4,5 - 2\(x\) = -0,5
2\(x\) = 4,5 + 0,5
2\(x\) = 5
\(x\) = 5: 2
\(x\) = 2,5
a, \(\left(2,8x-32\right):\dfrac{2}{3}=-90\)
\(\Rightarrow2,8x-32=-60\)
\(\Rightarrow2,8x=-28\)
\(\Rightarrow x=-10\)
Vậy x = -10
b, \(\left(4,5-2x\right):1\dfrac{4}{7}=\dfrac{11}{14}\)
\(\Rightarrow\left(4,5-2x\right):\dfrac{11}{7}=\dfrac{11}{14}\)
\(\Rightarrow4,5-2x=\dfrac{121}{98}\)
\(\Rightarrow2x=\dfrac{160}{49}\)
\(\Rightarrow x=\dfrac{80}{49}\)
Vậy \(x=\dfrac{80}{49}\)
\(a,\left(2,8x-32\right):\dfrac{2}{3}=-90\)
\(2,8x-32=-90.\dfrac{2}{3}\)
\(2,8x-32=-60\)
\(2,8x=-60+32\)
\(2,8x=-28\)
\(x=-28:2,8\)
\(x=-10\)
Vậy \(x=-10\)
\(b,\left(4,5-2x\right):1\dfrac{4}{7}=\dfrac{11}{14}\)
\(\left(4,5-2x\right):\dfrac{11}{7}=\dfrac{11}{14}\)
\(4,5-2x=\dfrac{11}{14}.\dfrac{11}{7}\)
\(4,5-2x=\dfrac{121}{98}\)
\(2x=4,5-\dfrac{121}{98}\)
\(2x=\dfrac{160}{49}\)
\(x=\dfrac{160}{49}:2\)
\(x=\dfrac{80}{49}\)
Vậy \(x=\dfrac{80}{49}\)
Ta có : 4,5 - 2x * 147 = 11/14 .
⇒ 9/2 - 2x * 147 = 11/14 .
⇒ 2x * 147 = 9/2 - 11/14 .
⇒ 2x * 147 = 63/14 - 11/14 .
⇒ 2x * 147 = 26/7 .
⇒ 2x = 26/7 : 147 .
⇒ 2x = ( 26 * 147 ) / 7 .
⇒ 2x = 78 .
⇒ x = 78 : 2 .
⇒ x = 39 .
Vậy x = 39 .
\(4,5-2x\cdot147=\dfrac{11}{14}\\ 2x\cdot147=4,5-\dfrac{11}{14}\\ 2x\cdot147=\dfrac{52}{14}\\ 2x=\dfrac{52}{14}:147\\ 2x=\dfrac{26}{1029}\\ x=\dfrac{26}{1029}:2\\ x=\dfrac{13}{1029}\\ Vậy...\)