5(x-2)^2+2(x-3)^2-8(x+4)^2 tim gtln
x^4-7x^2+4x+25
(x+3)^4+(x-7)^4
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28 tháng 8 2019
a) = (x+3).(x-3)^2-(x-3)(x+3)^2
=(x^2-9)(x-3)-(x^2-9)(x+3)
=(x^2-9)(x-3-x-3)
=-6(x^2-9)
các câu còn lại tương tự
28 tháng 8 2019
\(a,\left(x+3\right)\left(x^2-3x+9\right)-\left(x-3\right)\left(x^2+3x+9\right)\)
\(=x^3+3-\left(x^3-3\right)\)
\(=x^3+3-x^3+3\)
\(=6\)
\(b,\left(x-5\right)\left(x^2+5x+25\right)-\left(x+5\right)\left(x^2-5x+25\right)\)
\(=x^3-5^3-x^3-5^3\)
\(=-125-125\)
\(=-250\)
13 tháng 12 2021
Bài 2:
a: \(\Leftrightarrow\left(x-2\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
16 tháng 10 2021
\(1,\\ a,=7x^3-49x^2+21x\\ b,=x^2-x-42\\ c,=x^2-16x+64\\ d,=9x^2+12x+4\\ e,=x^2-16-25+10x-x^2=10x-41\\ 2,\\ a,\Rightarrow2\left(x-7\right)=19\\ \Rightarrow x-7=\dfrac{19}{2}\Rightarrow x=\dfrac{33}{2}\\ b,\Rightarrow4x^2-20x+25-4x^2+3x-2x=50\\ \Rightarrow-19x=25\Rightarrow x=-\dfrac{25}{19}\)
22 tháng 10 2021
\(a,=x^2-4x+4-\dfrac{15}{4}=\left(x-2\right)^2-\dfrac{15}{4}=\left(x-2-\dfrac{\sqrt{15}}{2}\right)\left(x-2+\dfrac{\sqrt{15}}{2}\right)\\ b,=?\\ c,\Rightarrow x^2+7x-8=0\\ \Rightarrow\left(x+8\right)\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=-8\\x=1\end{matrix}\right.\\ d,Sửa:x^3-3x^2=-27+9x\\ \Rightarrow x^3-3x^2+9x-27=0\\ \Rightarrow x^2\left(x-3\right)+9\left(x-3\right)=0\\ \Rightarrow\left(x^2+9\right)\left(x-3\right)=0\Rightarrow\left[{}\begin{matrix}x^2=-9\left(vô.lí\right)\\x=3\end{matrix}\right.\\ \Rightarrow x=3\\ e,\Rightarrow x\left(x-3\right)-7x+21=0\\ \Rightarrow x\left(x-3\right)-7\left(x-3\right)=0\\ \Rightarrow\left(x-7\right)\left(x-3\right)=0\Rightarrow\left[{}\begin{matrix}x=7\\x=3\end{matrix}\right.\\ f,\Rightarrow x^2\left(x-2\right)+\left(x-2\right)=0\\ \Rightarrow\left(x^2+1\right)\left(x-2\right)=0\Rightarrow\left[{}\begin{matrix}x^2=-1\left(vô.lí\right)\\x=2\end{matrix}\right.\\ \Rightarrow x=2\)
\(g,\Rightarrow x^2-4x+4=0\\ \Rightarrow\left(x-2\right)^2=0\\ \Rightarrow x=2\\ h,Sửa:x^3-x^2+x=1\\ \Rightarrow x^2\left(x-1\right)+\left(x-1\right)=0\\ \Rightarrow\left(x^2+1\right)\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x^2=-1\left(vô.lí\right)\\x=1\end{matrix}\right.\\ \Rightarrow x=1\)
19 tháng 8
1: \(x^2+3x+2\)
\(=x^2+x+2x+2\)
=x(x+1)+2(x+1)
=(x+1)(x+2)
2: \(x^2+4x+3\)
\(=x^2+x+3x+3\)
=x(x+1)+3(x+1)
=(x+1)(x+3)
3: \(x^2+5x+4\)
\(=x^2+x+4x+4\)
=x(x+1)+4(x+1)
=(x+1)(x+4)
4: \(x^2-4x+3\)
\(=x^2-x-3x+3\)
=x(x-1)-3(x-1)
=(x-1)(x-3)
5: \(x^2-4x+4=x^2-2\cdot x\cdot2+2^2=\left(x-2\right)^2\)
6: \(x^2-5x+4\)
\(=x^2-x-4x+4\)
=x(x-1)-4(x-1)
=(x-1)(x-4)
7: \(x^2-5x+6\)
\(=x^2-2x-3x+6\)
=x(x-2)-3(x-2)
=(x-2)(x-3)
8: \(x^2+6x+5\)
\(=x^2+x+5x+5\)
=x(x+1)+5(x+1)
=(x+1)(x+5)
9: \(x^2-7x+10\)
\(=x^2-2x-5x+10\)
=x(x-2)-5(x-2)
=(x-2)(x-5)
10: \(x^2+8x+12\)
\(=x^2+2x+6x+12\)
=x(x+2)+6(x+2)
=(x+2)(x+6)
11: \(x^2-8x+16=x^2-2\cdot x\cdot4+4^2=\left(x-4\right)^2\)
12: \(x^2+8x+15\)
\(=x^2+3x+5x+15\)
=x(x+3)+5(x+3)
=(x+3)(x+5)
13: \(x^2-8x+7\)
\(=x^2-x-7x+7\)
=x(x-1)-7(x-1)
=(x-1)(x-7)
14: \(x^2+9x+8\)
\(=x^2+x+8x+8\)
=x(x+1)+8(x+1)
=(x+1)(x+8)
15: \(x^2-9x+14\)
\(=x^2-2x-7x+14\)
=x(x-2)-7(x-2)
=(x-2)(x-7)
16: \(x^2+9x+18\)
\(=x^2+3x+6x+18\)
=x(x+3)+6(x+3)
=(x+3)(x+6)
17: \(x^2-9x+20\)
\(=x^2-4x-5x+20\)
=x(x-4)-5(x-4)
=(x-4)(x-5)
18: \(2x^2-3x+1\)
\(=2x^2-2x-x+1\)
=2x(x-1)-(x-1)
=(x-1)(2x-1)
S
subjects
CTVHS
19 tháng 8
1. \(x^2+3x+2=\left(x+1\right)\left(x+2\right)\)
2. \(x^2+4x+3=\left(x+1\right)\left(x+3\right)\)
3. \(x^2+5x+4=\left(x+1\right)\left(x+4\right)\)
4. \(x^2-4x+3=\left(x-1\right)\left(x-3\right)\)
5. \(x^2-4x+4=\left(x-2\right)^2\)
6. \(x^2-5x+4=\left(x-1\right)\left(x-4\right)\)
7. \(x^2-5x+6=\left(x-2\right)\left(x-3\right)\)
8. \(x^2+6x+5=\left(x+1\right)\left(x+5\right)\)
9. \(x^2-7x+10=\left(x-2\right)\left(x-5\right)\)
10. \(x^2+8x+12=\left(x+2\right)\left(x+6\right)\)
11. \(x^2-8x+16=\left(x-4\right)^2\)
12. \(x^2+8x+15=\left(x+3\right)\left(x+5\right)\)
13. \(x^2-8x+7=\left(x-1\right)\left(x-7\right)\)
14. \(x^2+9x+8=\left(x+1\right)\left(x+8\right)\)
15. \(x^2-9x+14=\left(x-2\right)\left(x-7\right)\)
16. \(x^2+9x+18=\left(x+3\right)\left(x+6\right)\)
17. \(x^2-9x+20=\left(x-4\right)\left(x-5\right)\)
\(18.2x^2-3x+1=2x^2-x-2x+1\)
\(=x\cdot\left(2x-1\right)-\left(2x-1\right)=\left(2x-1\right)\left(x-1\right)\)
21 tháng 2 2021
1: Ta có: 7x+6(3-x)=27-20+73
\(\Leftrightarrow7x+18-6x=80\)
\(\Leftrightarrow x=80-18=62\)
Vậy: x=62
2: Ta có: \(6x-5\left(x-7\right)=\left(27-514\right)-486-73\)
\(\Leftrightarrow6x-5x+35=27-514-486-73\)
\(\Leftrightarrow x+35=-1046\)
\(\Leftrightarrow x=-1081\)
Vậy: x=-1081
