so sanh : 1/2010 va -7/19
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PQ
0
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Y
1
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13 tháng 7 2016
\(A=\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}\)
\(B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\frac{-9}{10^{2010}}>\frac{-19}{10^{2010}}\)
\(\Rightarrow\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}>\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\Rightarrow A>B\)
TN
2
TC
0
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NT
0
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DV
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A
1
ta có : \(\dfrac{1}{2010}>0\) và \(\dfrac{-7}{19}< 0\)
\(\Rightarrow\dfrac{1}{2010}>\dfrac{-7}{19}\)
\(\dfrac{1}{2010}\) > \(\dfrac{-7}{19}\)