Question

[DOREAMON]

-5<x<1

|x|<3

(x-3)(x-5)<0

giúp mk vs các bn

Answer 1

[Hoang Hung Quan]

a) \(-5< x< 1\)

\(\Leftrightarrow x\in\left\{-4;-3;-2;-1;0\right\}\)

b) Ta có: \(\left|x\right|< 3\)

Mà \(\left\{{}\begin{matrix}\left|x\right|\ge0\\\left|x\right|< 3\end{matrix}\right.\) nên \(0\le\left|x\right|< 3\)

\(\Rightarrow\left|x\right|\in\left\{0;1;2\right\}\Leftrightarrow x\in\left\{0;\pm1;\pm2\right\}\)

Vậy \(x\in\left\{0;\pm1;\pm2\right\}\)

c) Ta có: \(\left(x-3\right)\left(x-5\right)< 0\)

\(\Leftrightarrow x-3\) và \(x-5\) trái dấu

Dễ thấy \(x-5< x-3\)

Nên \(\left\{{}\begin{matrix}x-5< 0\\x-3>0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x< 5\\x>3\end{matrix}\right.\) \(\Leftrightarrow3< x< 5\)

Vậy \(3< x< 5\)

Answer 2

[fghfghf]

a)0,-1.-2.-3,-4

1,-1,2,-2

4