Given that a^2-b^2=1. Evaluate: A=2(a^6-b^6)-3(a^4-b^4)
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Đa thức chia x-1 có ngiệm là 1 nên:
Thay x=1 vào đa thức chia ta có:
130+14-11975+1
=1+1-1+1
=2
Vậy số dư khi chia khi chia x30+x4-x1975+1 cho x-1 là 2
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\(\frac{x^3+x^2-4x-4}{x^3+8x^2+17x+10}=\frac{x^2\left(x+1\right)-4\left(x+1\right)}{x^2\left(x+1\right)+7x\left(x+1\right)+10\left(x+1\right)}\)
\(=\frac{\left(x+1\right)\left(x^2-4\right)}{\left(x+1\right)\left(x^2+7x+10\right)}=\frac{\left(x+2\right)\left(x-2\right)}{x\left(x+2\right)+5\left(x+2\right)}\)
\(=\frac{\left(x+2\right)\left(x-2\right)}{\left(x+2\right)\left(x+5\right)}=\frac{x-2}{x+5}\Rightarrow a=-2;b=5\)
\(\Rightarrow\)\(a+b=-2+5=3\)
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We know that a & 3 = (a+b)(a-b); therefore, 4 & 3 = (4-3)(4+3) = 7
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Evaluate the expression at
x3 + 12x + 48x + 64
= (x + 4)2
= (- 4 + 4)2
= 02
= 0
Fill in the blank: ............
x3 - a = (x - 2)(x2 + 2x + 4)
x3 - a = x3 - 8
a = 8
Evaluate
Answer:
a + b = 8
(a + b)2 = 82
a2 + b2 + 2ab = 64
a2 + b2 + 2 . 10 = 64
a2 + b2 + 20 = 64
a2 + b2 = 64 - 20
a2 + b2 = 44
(a - b)2
= a2 - 2ab + b2
= 44 - 2 . 10
= 44 - 20
= 24
Given .
Evaluate A at .
Answer: A
A = (x - 5)(x2 + 5x + 25) - x2(x + 3) + 3x2
= x3 - 125 - x3 - 3x2 + 3x2
= - 125
Given .
Evaluate A at .
Answer: A
Answer:
Given
Answer:
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giải
Ta có : \(\left(a+b\right)^2=\left(a-b\right)^2+4ab\)
Với \(a-b=8\)và \(ab=10\)
\(\Rightarrow\left(a+b\right)^2=8^2+4\times10\)
\(=104\)
mk nghĩ là -1
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