\(\frac{35x6}{672}\)giải giúp mình nha các bạn
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So sánh 22015 và 9672
9672 > 8672
8672=(23)672=23.672=22016
=> 22015 < 22016
=> 22015 > 22016 < 9672
Vậy 22015 < 9672
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Bài làm:
Ta có: \(\frac{131313}{151515}+\frac{131313}{353535}+\frac{131313}{636363}+\frac{131313}{999999}\)
\(=\frac{13}{15}+\frac{13}{35}+\frac{13}{63}+\frac{13}{99}\)
\(=\frac{13}{2}\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)
\(=\frac{13}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
\(=\frac{13}{2}\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(=\frac{13}{2}.\frac{8}{33}=\frac{52}{33}\)
\(\frac{131313}{151515}+\frac{131313}{353535}+\frac{131313}{636363}+\frac{131313}{999999}\)
\(=\frac{13}{15}+\frac{13}{35}+\frac{13}{63}+\frac{13}{99}\)
\(=13\left(\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}\right)\)
\(=13\left(\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}\right)\)
\(=13\left[\frac{1}{2}\left(\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+\frac{2}{9\cdot11}\right)\right]\)
\(=13\left[\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{9}-\frac{1}{11}\right)\right]\)
\(=13\left[\frac{1}{2}\left(\frac{1}{3}-\frac{1}{11}\right)\right]=13\cdot\frac{1}{2}\cdot\frac{8}{33}=\frac{52}{33}\)
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\(=\frac{y+x+z+4}{x+4+y+z}=1\)
từ \(\frac{y+x}{x+4}=1\Rightarrow y+x=x+4\Rightarrow y=4\)
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gọi các phân số cần tìm là\(\frac{a}{12}\)
ta có \(\frac{-2}{3}\)< \(\frac{a}{12}\)< \(\frac{-1}{4}\)
suy ra \(\frac{-8}{12}\)< \(\frac{a}{12}\)< \(\frac{-4}{12}\)
suy ra -8 < a < -4
vậy A thuộc { -7,-6,-5 }
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Có 2 cách
C1: \(\frac{x}{21}=\frac{y}{14}\Rightarrow\frac{3x}{63}=\frac{7y}{98}=\frac{3x-7y}{63-98}=\frac{70}{-35}=-2\\ \)=> \(\hept{\begin{cases}3x=63.\left(-2\right)\\7y=98\left(-2\right)\end{cases}\Rightarrow\hept{\begin{cases}x=-42\\y=-28\end{cases}}}\)
C2
\(\frac{x}{21}=\frac{y}{14}\Rightarrow x=\frac{21}{14}y=\frac{3}{2}y\\ \)
Mà \(3x-7y=70\Rightarrow3.\frac{3}{2}y-7y=70\Rightarrow-\frac{5}{2}y=70\Rightarrow y=-28\Rightarrow x=-42\)
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mình đã đăng mấy bài toán rồi,bạn thông cảm kiếm đề toán của mình nha ^.^
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\(\frac{9^2.27^4}{3.81^3}\)=\(\frac{3^4.3^{12}}{3.3^{12}}\)=\(\frac{3^3.1}{1.1}\)=\(3^3\)
TK MIK NHA