tìm x, biết ; 5^x + 5^x+2=650
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\(2015-\left|x-2015\right|=x\)
\(\Leftrightarrow\left|x-2015\right|=2015-x\)
\(\Leftrightarrow\orbr{\begin{cases}x-2015=2015-x\\x-2015=-\left(2015-x\right)\end{cases}}\)
\( TH1:x-2015=2015-x\)
\(\Leftrightarrow2x=4030\)
\(\Leftrightarrow x=\frac{4030}{2}\)
\(\Leftrightarrow x=2015\)
\(TH2:x-2015=-\left(2015-x\right)\)
\(\Leftrightarrow x-2015=x-2015\)
Vậy x = 2015
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\(TH1:x\ge3\). PT có dạng:\(x-3=x-5\)
\(\Leftrightarrow0x=-2\)
\(\Rightarrow x\in\)tập rỗng
\(TH2:x< 3\). PT có dạng:\(-\left(x-3\right)=x-5\)
\(\Leftrightarrow3-x=x-5\)
\(\Leftrightarrow-2x=-8\)
\(\Leftrightarrow x=4\left(koTM\right)\)
Vậy PT vô nghiệm
lx-3l = x-5
=) x-3 = x-5 -) x-3-x+5 = 0 =) 2=0 (vô lí)
x-3 = -(x-5) -) 2x=8 =) x=4
vậy x=4
chúc bn học tốt , nếu có chỗ nào ko hỉu thì cứ hỏi mk nhé
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x + (x + 1) + (x + 2) + ... + (x + 2003) = 2004
=> x + x + 1 + x + 2 + .... + x + 2003 = 2004
=> 2004x + 2007006 = 2004
=> 2004x = 2005002
=> x = 1000,5
Ta có: \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+2003\right)=2004\)
\(\Leftrightarrow2004x+2007006=2004\)
\(\Leftrightarrow2004x=-2005002\)
hay \(x=-\dfrac{2001}{2}\)
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kết quả x=2
5x..1+5x.52=650
Ai h mk mk se h lai