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10:5/3= 10x3/5=6
5/3:10=5/3x1/10=1/6
12/35:35/25=12/35x25/35=300/1225=12/49
19/17:76/51=19/17x 51/76= 3/4
\(10:\frac{5}{3}=10x\frac{3}{5}=\frac{30}{5}=6\)
\(\frac{5}{3}:10=\frac{5}{3}x\frac{1}{10}=\frac{5}{30}=\frac{1}{6}\)
\(\frac{12}{35}:\frac{35}{25}=\frac{12}{35}x\frac{25}{35}=\frac{12}{35}x\frac{5}{7}=\frac{12}{7}x\frac{1}{7}=\frac{12}{49}\)
\(\frac{19}{17}:\frac{76}{51}=\frac{19}{17}x\frac{51}{76}=\frac{1}{1}x\frac{3}{4}=\frac{3}{4}\)
Thank you! Chúc bạn học tốt!

\(\Rightarrow3\left(12+x\right)=2\left(43+x\right)\)
\(\Leftrightarrow36+3x=86+2x\)
\(\Leftrightarrow x=86-36=50\)

\(\frac{12+x}{43-x}=\frac{2}{3}\)
2 ( 43 - x ) = 3 ( 12 + x )
86 - 2x = 36 + 3x
86 - 36 = 3x + 2x
5x = 50
x = 10
Vậy,......
(12 + x) . 3 = (43 - x) . 2
36 + 3x = 86 - 2x
86 - 36 = 3x + 2x
50 = 5x
x = 50 : 5
x = 10

\(\frac{12+X}{43-X}=\frac{2}{3}\Rightarrow\frac{\left(12+X\right)x3}{\left(43-X\right)x3}=\frac{\left(43-X\right)x2}{\left(43-X\right)x3}\)
\(\Rightarrow\left(12+X\right)x3=\left(43-X\right)x2\)
\(\Rightarrow36+3xX=86-2xX\)
\(\Rightarrow3xX+2xX=86-36\)
\(\Rightarrow5xX=30\Rightarrow X=30:5=6\)
Vậy x bằng 6

\(\frac{12+x}{43-x}=\frac{2}{3}\)
\(\Rightarrow\frac{\left(12+x\right)\times3}{\left(43-x\right)\times3}=\frac{2\times\left(43-x\right)}{\left(43-x\right)\times3}\)
\(\Rightarrow\frac{36+3x}{129-3x}=\frac{86-2x}{129-3x}\)
\(\Rightarrow\frac{36+3x}{129-3x}-\frac{86-2x}{129-3x}=0\)
\(\Rightarrow\frac{36+3x-86+2x}{129-3x}\)
\(\Rightarrow\frac{-50+5x}{129-3x}\)
k cho minh

12 + x / 43 - x có tổng là 12 + 43 = 55
Tổng số phần bằng nhau :
2 + 3 = 5 ( phần )
Giá trị 1 phần :
55 : 5 = 11
x là :
( 11 x 2 ) - 12 = 10
\(\frac{12+x}{43-x}=\frac{2}{3}\)
\(\Leftrightarrow2\left(43-x\right)=3\left(12+x\right)\)
\(\Leftrightarrow86-2x=36+3x\)
\(\Leftrightarrow86-36=3x+2x\)
\(\Leftrightarrow50=5x\Leftrightarrow x=10\)

a, \(\frac{6+x}{33}=\frac{7}{11}\)
\(\Leftrightarrow\left(6+x\right).11=7.33\)
\(\Leftrightarrow66+11x=231\)
\(\Leftrightarrow11x=231-66\)
\(\Leftrightarrow x=\frac{165}{11}=15\)
Vậy x = 15.
b,\(\frac{12+x}{43-x}=\frac{2}{3}\)
\(\Leftrightarrow3.\left(12+x\right)=2\left(43-x\right)\)
\(\Leftrightarrow36+3x=86-2x\)
\(\Leftrightarrow3x+2x=-36+86\)
\(\Leftrightarrow5x=50\)
\(\Leftrightarrow x=10\)
Vây x = 10.


a) \(\frac{9}{22}.\frac{33}{18}=\frac{9.33}{22.18}=\frac{297}{396}=\frac{3}{4}\)
b) \(\frac{12}{35}:\frac{36}{25}=\frac{12}{35}.\frac{25}{36}=\frac{12.25}{35.36}=\frac{300}{1260}=\frac{5}{21}\)
c) \(\frac{19}{17}:\frac{76}{51}=\frac{19}{17}.\frac{51}{76}=\frac{19.51}{17.76}=\frac{969}{1292}=\frac{3}{4}\)
Ta có: 103+[12x(43x2-76)]+277
=103+277+12x(86-76)
=380+12x10
=380+120
=500
103 + [12×(43×2-76)] + 277
= 103 + [12×(86-76)] + 277
= 103 + [12×10] + 277
= 103 + 120+ 277
= 223 + 277
= 500