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a) \(227+50+23=\left(227+23\right)+50=250+50=300\)
b) \(135+360+65+40=\left(135+65\right)+\left(360+40\right)=200+400=600\)
c) \(1+2+3+4+5+...+97+98+99+100\)
\(=\left(100+1\right)+\left(99+2\right)+...+\left(50+51\right)\)
\(=101+101+101+...+101\)
\(=101\cdot50\)
\(\Leftrightarrow5050\)
d) \(115\cdot13-13\cdot15=13\cdot\left(115-15\right)=13\cdot100=1300\)
e) \(50-49+48-47+...+4-3+2-1\)
\(=\left(50-49\right)+\left(48-47\right)+...+\left(2-1\right)\)
\(=1+1+1+1+..+1\)
\(=1\cdot25\)
\(=25\)
f) \(30\cdot40\cdot50\cdot60=10\cdot3+10\cdot4+10\cdot5+10\cdot6\)
\(=10\cdot10\cdot10\cdot10\cdot3\cdot4\cdot5\cdot6\)
\(=10000\cdot360\)
\(=3600000\)
g) \(27\cdot36+27\cdot64=27\cdot\left(36+64\right)=27\cdot100=2700\)
h) \(5\cdot2^2-18:3=5\cdot4-18:3=20-6=14\)
i) \(13\cdot17-256:16+14:7-2021^0\)
\(=13\cdot17-4^4:4^2+2-1\)
\(=13\cdot17-16+2-1\)
\(=13\cdot17-17\)
\(=17\cdot\left(13-1\right)\)
\(=204\)
j) \(7^2-36:3=49-12=37\)


\(\frac{1}{3}.\frac{5}{7}-\frac{7}{27}.\frac{36}{14}\)
\(=\frac{1}{3}.\frac{5}{7}-\frac{7}{27}.\frac{18}{7}\)
\(=\frac{1.5}{3.7}-\frac{7.18}{27.7}\)
\(=\frac{5}{21}-\frac{2}{3}\)
\(=\frac{5}{21}-\frac{14}{21}=\frac{-9}{21}=\frac{-3}{7}\)
Chúc bn học tốt
Tính nhanh
a) 27.26 + 27.64
b) 25.37 + 25.63 - 150
c) 425.7.4 = 170.60
d) 0.9.14 + 6.17.12 + 19.4.18

a, 27.26+27.64
=27.(26+64)
=27.90
=2430
b,25.37+25.63-150
=25.(37+63)-150
=25.110-150
=2750-150
=2600
c,425.7.4=170.60
=1700.7=170.10.6
=1700.7-1700.6
=1700.(7-6)
=1700
d,0.9.14+6.17.12+19.4.18
=0+6.17.12+19.4.18
=6.3.4.17+19.4.18
=18.4.17+19.4.18
=18.4.(17+19)
=72.36=2592

A = 27.36+73.99+27.14-49.73
A=27(36+14)+73(99-49)
A=27.50+79.50
A=50(27+79)
A=50.100=5000
27 . 36 + 73 . 99 + 27 . 14 - 49 . 73 = 27 . ( 36 + 14 ) + 73 . ( 99 - 49 )
= 27 . 50 + 73 . 50
= 50 . ( 73 + 27 )
= 50 . 100
= 5000
CHÚC BẠN HOK GIỎI :))

a, A = 27.36+73.99+27.14 - 49.73
= 27(36+14)+73(99 - 49)
= 27.50 + 73.50 = 50(27+73) = 50.100 = 5000
b, B = 4 5 . 10 . 5 6 + 25 5 . 2 8 : 2 8 . 5 4 + 5 7 . 2 5
Ta có: 4 5 = 2 2 5 = 2 2 . 5 = 2 10 ; 25 5 = 5 2 5 = 5 2 . 5 = 5 10
=> 4 5 . 10 . 5 6 + 25 5 . 2 8 = 2 10 . 2 . 5 . 5 6 + 5 10 . 2 8 = 2 11 . 5 7 + 5 10 . 2 8 = 2 8 . 2 3 . 5 7 + 5 7 . 5 3 . 2 8 = 2 8 . 5 7 . 2 3 + 5 3
Ta lại có: 2 8 . 5 4 + 5 7 . 2 5 = 2 5 . 2 3 . 5 4 + 5 4 . 5 3 . 2 5 = 2 5 . 5 4 . 2 3 + 5 3
Suy ra B = 2 8 . 5 7 . 2 3 + 5 3 :[ 2 5 . 5 4 . 2 3 + 5 3 ] = 2 8 . 5 7 : 2 5 . 5 4
= 2 8 : 2 5 . 5 7 : 5 4 = 2 3 . 5 3 = 2 . 5 3 = 10 3 = 1000
a, A = 27.36+73.99+27.14 - 49.73
= 27(36+14)+73(99 - 49)
= 27.50 + 73.50 = 50(27+73) = 50.100 = 5000
b, B = 4 5 . 10 . 5 6 + 25 5 . 2 8 : 2 8 . 5 4 + 5 7 . 2 5
Ta có: 4 5 = 2 2 5 = 2 2 . 5 = 2 10 ; 25 5 = 5 2 5 = 5 2 . 5 = 5 10
=> 4 5 . 10 . 5 6 + 25 5 . 2 8 = 2 10 . 2 . 5 . 5 6 + 5 10 . 2 8 = 2 11 . 5 7 + 5 10 . 2 8 = 2 8 . 2 3 . 5 7 + 5 7 . 5 3 . 2 8 = 2 8 . 5 7 . 2 3 + 5 3
Ta lại có: 2 8 . 5 4 + 5 7 . 2 5 = 2 5 . 2 3 . 5 4 + 5 4 . 5 3 . 2 5 = 2 5 . 5 4 . 2 3 + 5 3
Suy ra B = 2 8 . 5 7 . 2 3 + 5 3 :[ 2 5 . 5 4 . 2 3 + 5 3 ] = 2 8 . 5 7 : 2 5 . 5 4
= 2 8 : 2 5 . 5 7 : 5 4 = 2 3 . 5 3 = 2 . 5 3 = 10 3 = 1000

\(\frac{1}{2}\cdot\left(\frac{2}{9}+\frac{3}{7}-\frac{5}{27}\right)=\frac{1}{2}\cdot\left(\frac{6}{27}-\frac{5}{27}+\frac{3}{7}\right)=\frac{1}{2}\cdot\frac{3}{7}+\frac{1}{2}\cdot\frac{1}{27}=\frac{3}{14}+\frac{1}{54}=\frac{44}{189}\)
\(\frac{1}{2}+\frac{3}{4}-\left(\frac{3}{4}-\frac{4}{5}\right)=\frac{1}{2}+\frac{3}{4}-\frac{3}{4}+\frac{4}{5}=\frac{1}{2}+\frac{4}{5}=\frac{13}{10}\)
\(\frac{1}{3}\cdot\frac{5}{7}-\frac{7}{27}\cdot\frac{36}{14}=\frac{1}{3}\cdot\frac{5}{7}-\frac{7}{27}\cdot\frac{18}{7}=\frac{1}{3}\cdot\frac{5}{7}-\frac{6}{7}=\frac{5}{21}-\frac{14}{21}=\frac{-3}{7}\)

a: \(=\dfrac{1}{2}\cdot\dfrac{2\cdot21+3\cdot27-5\cdot7}{189}\)
\(=\dfrac{1}{2}\cdot\dfrac{88}{189}=\dfrac{44}{189}\)
b: \(=\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{3}{4}+\dfrac{4}{5}=\dfrac{1}{2}+\dfrac{4}{5}=\dfrac{13}{10}\)
c: \(=\dfrac{5}{21}-\dfrac{7}{14}\cdot\dfrac{36}{27}=\dfrac{5}{21}-\dfrac{1}{2}\cdot\dfrac{4}{3}=\dfrac{5}{21}-\dfrac{2}{3}=\dfrac{5-14}{21}=\dfrac{-9}{21}=\dfrac{-3}{7}\)
=27.(36+64)
=27.100
=2700
27.36+27.64
=27.(36+64)
= 27.100
= 2 700