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\(x\cdot\frac{1}{3}:\frac{2}{5}=\frac{4}{3}\)
\(\Rightarrow x\cdot\frac{1}{3}=\frac{4}{3}\cdot\frac{2}{5}\)
\(\Rightarrow x\cdot\frac{1}{3}=\frac{8}{15}\)
\(\Rightarrow x=\frac{8}{15}:\frac{1}{3}\)
\(\Rightarrow x=\frac{8}{5}\)
Vậy x=........
\(x.\frac{1}{3}:\frac{2}{5}=\frac{4}{3}\)
\(x.\frac{1}{3}=\frac{4}{3}x\frac{2}{5}=\frac{8}{15}\)
\(x=\frac{8}{15}:\frac{1}{3}=\frac{8}{5}\)
học tốt
Bài 1 Tìm số tự nhiên x biết
a, \(\frac{3}{x}\)> \(\frac{3}{5}\)
b, \(\frac{1}{5}\)< \(\frac{x}{5}\)
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a, \(\frac{5}{11}\times\frac{7}{25}+\frac{15}{11}\times\frac{1}{5}\)
\(=\frac{5}{11}\times\frac{7}{25}+\frac{5}{11}\times\frac{3}{5}\)
\(=\frac{5}{11}\times\left(\frac{7}{25}+\frac{3}{5}\right)\)
\(=\frac{5}{11}\times\frac{22}{25}\)
\(=\frac{2}{5}\)
b, \(\frac{3}{7}\times\frac{25}{19}-\frac{1}{7}\times\frac{18}{19}\)
\(=\frac{1}{7}\times\frac{75}{19}-\frac{1}{7}\times\frac{18}{19}\)
\(=\frac{1}{7}\times\left(\frac{75}{19}-\frac{18}{19}\right)\)
\(=\frac{1}{7}\times3\)
\(=\frac{3}{7}\)
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\(\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+....+\frac{1}{19.21}\right).x=\frac{9}{7}\)
\(\left(\frac{5-3}{3.5}+\frac{7-5}{5.7}+\frac{9-7}{7.9}+...+\frac{21-19}{19.21}\right).x=\frac{9}{7}\)
\(\left[\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{19}-\frac{1}{21}\right)\right].x=\frac{9}{7}\)
\(\left[\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{21}\right)\right].x=\frac{9}{7}\)
\(\left[\frac{1}{2}.\frac{2}{7}\right].x=\frac{9}{7}\)
\(\frac{1}{7}.x=\frac{9}{7}\)
\(\Rightarrow x=\frac{9}{7}\div\frac{1}{7}=9\)
\(\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{19.21}\right)x=\frac{9}{7}\)
\(\Leftrightarrow\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{19}-\frac{1}{21}\right)x=\frac{9}{7}\)
\(\Leftrightarrow\left(\frac{1}{3}-\frac{1}{21}\right)x=\frac{9}{7}\)
\(\Leftrightarrow\frac{2}{7}x=\frac{9}{7}\)
\(\Leftrightarrow x=\frac{9}{2}\)
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\(\frac{3}{2}x+\frac{1}{5}x=\frac{5}{8}\)
\(Xx\left(\frac{3}{2}+\frac{1}{5}\right)=\frac{5}{8}\)
\(x=\frac{5}{8}:\left(\frac{3}{2}+\frac{1}{5}\right)\)
\(x=\frac{25}{68}\)
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= [ 10 + 20 ] + [ 11 + 19 ] + [ 13 + 17 ] + 15
= 30 + 30 + 30 + 15
=105
10 + 11 + 13 + 15 + 17 + 19 + 20
= (10 + 20) + (11 + 19) + (13 + 17) + 15
= 30 + 30 + 30 + 15
= 105
\(1\frac{2}{3}+x=2\)
\(x=2-1\frac{2}{3}\)
\(x=\frac{1}{3}\)
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X=\(\frac{6}{5}.\frac{7}{6}....\frac{2015}{2014}\)
=\(\frac{2015}{5}\)
=403
ta có:
(x+1)+(x+3)+(x+5)+⋯+(x+19)=110
x+1+x+3+x+5+⋯+x+19=110
SSH(số số hạng): (19-1)/2+1=10
Tổng: (19+1)*10:2=100
suy ra 10x+100=110
= 10x =110-100
= 10x =10
suy ra x=1
\(\left(x+1\right)+\left(x+3\right)+\left(x+5\right)+...+\left(x+19\right)=110\)
\(\Rightarrow\left(x+x+x+...+x\right)+\left(1+3+5+...+19\right)=110\)
\(\Rightarrow10x+\left(19+1\right)\times10:2=110\)
\(\Rightarrow10x+20\times10:2=110\)
\(\Rightarrow10x+200:2=110\)
\(\Rightarrow10x+100=110\)
\(\Rightarrow10x=110-100\)
\(\Rightarrow10x=10\)
\(\Rightarrow x=10:10\)
\(\Rightarrow x=1\)
Vậy \(x=1\)